A small object with mass 4.15 kg moves counterclockwise with constant angular speed 1.30 rad/s in a circle of radius 3.30 m centered at the origin. It starts at the point with position vector 3.301 m. Then it undergoes an angular displacement of 9.30 rad. (a) What is its new position vector? -3.2671 +0.459j (b) In what quadrant is the object located and what angle does its position vector make with the positive x-axis? second at 172 (c) What is its velocity? -(0.597i - 4.24j) m/s (d) In what direction is it moving? (Give a negative angle.) o from the +x direction. (e) What is its acceleration? m/s² (f) What total force is exerted on the object? N

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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HELP WITH THIS PLEASE, DO NOT DO b ONLY THE OTHER

A small object with mass 4.15 kg moves counterclockwise with a constant angular speed of 1.30 rad/s in a circle of radius 3.30 m centered at the origin. It starts at the point with position vector \(3.30\hat{i}\) m. Then it undergoes an angular displacement of 9.30 rad.

**(a) What is its new position vector?**

Incorrect answer provided: \(-3.267\hat{i} + 0.459\hat{j}\) m

**(b) In what quadrant is the object located and what angle does its position vector make with the positive x-axis?**

Correct answer: Second quadrant at 172°.

**(c) What is its velocity?**

Incorrect answer provided: \((-0.597\hat{i} - 4.24\hat{j})\) m/s

**(d) In what direction is it moving? (Give a negative angle.)**

Blank for answer: ___° from the +x direction.

**(e) What is its acceleration?**

Blank for answer: ___ m/s\(^2\)

**(f) What total force is exerted on the object?**

Blank for answer: ___ N
Transcribed Image Text:A small object with mass 4.15 kg moves counterclockwise with a constant angular speed of 1.30 rad/s in a circle of radius 3.30 m centered at the origin. It starts at the point with position vector \(3.30\hat{i}\) m. Then it undergoes an angular displacement of 9.30 rad. **(a) What is its new position vector?** Incorrect answer provided: \(-3.267\hat{i} + 0.459\hat{j}\) m **(b) In what quadrant is the object located and what angle does its position vector make with the positive x-axis?** Correct answer: Second quadrant at 172°. **(c) What is its velocity?** Incorrect answer provided: \((-0.597\hat{i} - 4.24\hat{j})\) m/s **(d) In what direction is it moving? (Give a negative angle.)** Blank for answer: ___° from the +x direction. **(e) What is its acceleration?** Blank for answer: ___ m/s\(^2\) **(f) What total force is exerted on the object?** Blank for answer: ___ N
Expert Solution
Step 1: Given the values

Given data:

Mass of the object, m equals 4.15 space K g

Speed omega equals 1.30 space r a d divided by s

Radius  r equals 3.30 text  m end text

Angular displacement , theta equals 9.30 text  rad end text

Position vector, A equals 3.30 text  i m end text



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