An atomic emission spectrum of hydrogen shows three wavelengths: 121.6 nm, 102.6 nm, and 97. 26 nm. Assign these wavelengths to transitions in the hydrogen aton Match the items in the left column to the appropriate blanks in the sentences on the right. Reset Help n = 7 The wavelengths of the three transitions are visual region. Therefore, it can be assumed that the electrons return to the the wavelengths of the n =1 level. n=8 The difference in energy between the two levels ninitial and nfimal is given by the equation 6 equal to After calculating the energy difference using the given wavelengths, solving the equation for rinitial, and subtituting the proper values the following initial energy levels can be obtained: n=2 AE = -2.18 × 10-18 for 121.6nm, for 102.6nm, and 2 Tinitial ninal for 97.26nm. 3 AE = -2.18 × 10-18 ninal ninitial longer than n=5 1 AE = 1.1 × 107 | final initial shorter than
An atomic emission spectrum of hydrogen shows three wavelengths: 121.6 nm, 102.6 nm, and 97. 26 nm. Assign these wavelengths to transitions in the hydrogen aton Match the items in the left column to the appropriate blanks in the sentences on the right. Reset Help n = 7 The wavelengths of the three transitions are visual region. Therefore, it can be assumed that the electrons return to the the wavelengths of the n =1 level. n=8 The difference in energy between the two levels ninitial and nfimal is given by the equation 6 equal to After calculating the energy difference using the given wavelengths, solving the equation for rinitial, and subtituting the proper values the following initial energy levels can be obtained: n=2 AE = -2.18 × 10-18 for 121.6nm, for 102.6nm, and 2 Tinitial ninal for 97.26nm. 3 AE = -2.18 × 10-18 ninal ninitial longer than n=5 1 AE = 1.1 × 107 | final initial shorter than
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Transcribed Image Text:Part A
An atomic emission spectrum of hydrogen shows three wavelengths: 121.6 nm, 102.6 nm, and 97.26 nm. Assign these wavelengths to transitions in the hydrogen atom.
Match the items in the left column to the appropriate blanks in the sentences on the right.
Reset Help
n = 7
The wavelengths of the three transitions are
the wavelengths of the
n=1
visual region. Therefore, it can be assumed that the electrons return to the
level.
n = 8
n= 6
The difference in energy between the two levels ninitial and ninal is given by the
equation
equal to
n =2
After calculating the energy difference using the given wavelengths, solving the equation
for ninitial, and subtituting the proper values the following initial energy levels can be
for 121.6nm,
AE = -2.18 x 10-18
2
nnitial
obtained:
for 102.6nm, and
2
Tinal
for 97.26nm.
n=
3
1
1
AE = -2.18 x 10-18
nFinal
nnitial
n = 4
longer than
n = 5
1
AE = 1.1 × 107
ninal
initial
shorter than
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