Two protons at rest and separated by 6.00 mm are released simultaneously. What is the speed of either at the instant when the two are 10.00 mm apart?
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Two protons at rest and separated by 6.00 mm are released simultaneously. What is the speed of either at the instant when the two are 10.00 mm apart?
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- An electron is projected with an initial speed v; = 2.95 x 105 m/s directly toward a very distant proton that is at rest. Because the proton mass is large relative to the electron mass, assume that the proton remains at rest. By calculating the work done on the electron by the electrostatic force, determine the distance between the two particles when the electron instantaneously has speed 3vj. Number 0.0000000000000735 Units nm the tolerance is +/-2%(a) Find the electric potential difference AV required to stop an electron (called a "stopping potential") moving with an initial speed of 2.41 x 10 e m/s. kV (b) Would a proton traveling at the same speed require a greater or lesser magnitude of electric potential difference? O greater lesser O equal Explain. IA parallel plate capacitor has a surface charge density of σ = 0.0046 C/m2 on one plate. A small sphere charged to Q = 5.2E-06 C is moved a distance d = 0.17 m between the plates. Refer to the figure, which is not drawn to scale. At what speed, in meters per second, is the sphere moving when it reaches the distance d, if its mass is 0.10 kg and it starts from rest?
- Review Multiple-Concept Example 4 to see the concepts that are pertinent here. In a television picture tube, electrons strike the screen after being accelerated from rest through a potential difference of 24000 V. The speeds of the electrons are quite large, and for accurate calculations of the speeds, the effects of special relativity must be taken into account. Ignoring such effects, find the electron speed just before the electron strikes the screen. VB i eTextbook and Media GO Tutorial Save for Later Attempts: 0 of 6 used Submit AnswerAsapp plzzReview Multiple-Concept Example 4 to see the concepts that are pertinent here. In a television picture tube, electrons strike the screen after being accelerated from rest through a potential difference of 21000 V. The speeds of the electrons are quite large, and for accurate calculations of the speeds, the effects of special relativity must be taken into account. Ignoring such effects, find the electron speed just before the electron strikes the screen. VB =
- (a) Calculate the speed of a proton that is accelerated from rest through a potential difference of 12o v. km/s (b) Calculate the speed of an electron that is accelerated through the same potential difference. Mm/sTwo infinite sheets of equal and opposite charge are placed facing eachother with a distance of 1.50 m seperating them. The positive sheet is on the left and negative sheet on the right.If a lone point charge is -5.00 µC with a mass 3.15 *10^-7 kg is at the mid point between the plates and is released from rest, it reaches the positive sheet with a speed of 1200 m/s. Through what electric potential difference did the point charge move?What is the total potential difference between the plates? What is the surface densities of the plates? If the point charge had been released from at the position of the negative sheet from rest, with what speed would it reach the positive speed?Considering electron and proton as two charged particles separated by d = 4.3 x 10-11 m calculate the electrostatic potential at a distance d from the proton. Take the mass of the proton 1.7 x 10-27 kg, the mass of the electron 9.1 x 10-31 kg, the electron charge -1.6 × 10-¹⁹ 1 C and = 9 × 10⁹ m/F. Απευ Answer: Choose...
- (a) Calculate the speed of a proton that is accelerated from rest through an electric potential difference of 144 V. 166.11*10^3 (b) Calculate the speed of an electron that is accelerated through the same potential difference. 7.12*10^6(a) An electron is to be accelerated from 3.00 * 106 m/s to 8.00 * 106 m/s. Through what potential difference must the electron pass to accomplish this? (b) Through what potential difference must the electron pass if it is to be slowed from 8.00 * 106 m/s to a halt?Answers: a) 3.3 C c/m² 6. Two electrons are fixed 2.00 cm apart. Another electron is shot from infinity and comes to rest midway between the two. What was its initial speed? Answer: 318 m/s