The position of an object of mass 2.00 kg with respect to some origin is given as r = (6.00i + 5.00tj) m. Derive an expression for its angular momentum as a function of time.

Physics for Scientists and Engineers: Foundations and Connections
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Chapter13: Rotation Ii: A Conservation Approach
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Problem 45PQ: A thin rod of length 2.65 m and mass 13.7 kg is rotated at anangular speed of 3.89 rad/s around an...
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The position of an object of mass 2.00 kg with respect to some origin is given as r = (6.00i + 5.00tj) m. Derive an expression for its angular momentum as a function of time.

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I have a couple of follow up questions:

1) Is that 60k^  kgm^2/s, the SI unit for L

2) It wanted an expression as a function of time; so would it be L(t) = 60k, in which case it's 60k no matter what the value of t is?

Hopefully, I'm getting across what I mean. Thank you.

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