At the instant of the figure, a 1.6 kg particle P has a position vector of magnitude 1.7 m and angle 01 = 45° and a velocity vector v of magnitude 3.8 m/s and angle 02 = 30°. Force F of magnitude 1.6 N and angle 03 = 30° acts on P. All three vectors lie in the xy plane. (Express your answers in vector form.) (a) What is the angular momentum of the particle about the origin? kg • m2/s (b) What is the torque acting on the particle about the origin? そ= N. m Additional Materials
At the instant of the figure, a 1.6 kg particle P has a position vector of magnitude 1.7 m and angle 01 = 45° and a velocity vector v of magnitude 3.8 m/s and angle 02 = 30°. Force F of magnitude 1.6 N and angle 03 = 30° acts on P. All three vectors lie in the xy plane. (Express your answers in vector form.) (a) What is the angular momentum of the particle about the origin? kg • m2/s (b) What is the torque acting on the particle about the origin? そ= N. m Additional Materials
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Transcribed Image Text:= 30°. Force F of magnitude
= 45° and a velocity vector v of magnitude 3.8 m/s and angle 02
At the instant of the figure, a 1.6 kg particle P has a position vector r of magnitude 1.7 m and angle 01
1.6 N and angle 03
= 30° acts on P. All three vectors lie in the xy plane. (Express your answers in vector form.)
03
(a) What is the angular momentum of the particle about the origin?
kg · m2/s
(b) What is the torque acting on the particle about the origin?
デ=
N: m
Additional Materials
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