A particle moving in the x-y plane is subject to a central force F = f(r)Ã, where r = √x² + y² and F = cos x + sin 0ỹ. = (i) Write the velocity in terms of the polar coordinates r and 0, and thus find an expression for the angular momentum of the particle about the origin, also in terms of the polar coordinates. (ii) Show explicitly that the angular momentum is a constant of the motion. (iii) Derive an expression for the area dA swept out by the particle's position vector r during a small time interval dt (during which its angular displace- ment is de). Hence show that dA/dt is constant (Kepler's Third Law).

icon
Related questions
Question
A particle moving in the x-y plane is subject to a central force F = f(r)Ã, where
r = √x² + y² and F = cos x + sin 0ỹ.
=
(i) Write the velocity in terms of the polar coordinates r and 0, and thus find an
expression for the angular momentum of the particle about the origin, also
in terms of the polar coordinates.
(ii) Show explicitly that the angular momentum is a constant of the motion.
(iii) Derive an expression for the area dA swept out by the particle's position
vector r during a small time interval dt (during which its angular displace-
ment is de). Hence show that dA/dt is constant (Kepler's Third Law).
Transcribed Image Text:A particle moving in the x-y plane is subject to a central force F = f(r)Ã, where r = √x² + y² and F = cos x + sin 0ỹ. = (i) Write the velocity in terms of the polar coordinates r and 0, and thus find an expression for the angular momentum of the particle about the origin, also in terms of the polar coordinates. (ii) Show explicitly that the angular momentum is a constant of the motion. (iii) Derive an expression for the area dA swept out by the particle's position vector r during a small time interval dt (during which its angular displace- ment is de). Hence show that dA/dt is constant (Kepler's Third Law).
Expert Solution
steps

Step by step

Solved in 4 steps with 4 images

Blurred answer
Similar questions