A 3.6 µC charge is moved from a position where its electric potential energy is 7.2 mJ to a position where its potential energy is 1.8 mJ. What is the change in potential from the initial position to the final position? 3500 V -1500 V 2000 V 1500 V -2000 V
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Given:
The charge is .
The electric potential energy at point A is .
The electric potential energy at point B is .
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- The potential in a région between x = 0 and x = 6.00 m is V = a + bx, where a = 20.0 V and b = -6.50 V/m. (a) Determine the potential at x = 0. V Determine the potential at x = 3.00 m. V Determine the potential at x = 6.00 m. V (b) Determine the magnitude and direction of the electric field at x = 0. magnitude V/m direction ---Select--- C Determine the magnitude and direction of the electric field at x = 3.00 m. magnitude V/m direction ---Select--- Determine the magnitude and direction of the electric field at x = 6.00 m. magnitude V/m direction ---Select---The electric potential at a certain point in space is 12 V. What is the electric potential energy of a -3.0 μC charge placed at that point? O -4 µJ O +4 µJ O zero µJ O -36 J O +36 µJThere are two charges along the x-axis. q1 = 2.1 nC at x1 = 9.6 m q2 = 8 nC at x2 = 1.6 m What is the electric potential at the origin? Your answer should be in Volts. 1 nC = 10-9 C
- A moving particle encounters an external electric field that decreases its kinetic energy from 9140 eV to 5710 eV as the particle moves from position A to position B. The electric potential at A is -63.0 V, and that at B is +10.0 V. Determine the charge of the particle. Include the algebraic sign (+ or -) with your answer.In the figure (Figure 1), each capacitor has 5.00 μF and Vah 34.0 V Figure a b C₁ C₂ C₂ C₁ d Part A Calculate the charge on capacitor C₁ 17 ΑΣΦΑ 4 Q₁ = Submit Part B Calculate the potential difference across capacitor C₁- VG ΑΣΦ V₁ = Submit ▾ Part C Q₂- Calculate the charge on capacitor C₂. - ΑΣΦ ← A Submit Request Answer Y Part D Request Answer V₂= Request Answer Calculate the potential difference across capacitor C₂ [35] ΑΣΦ + C Submit Request Answer EXO O ? ? ? ? C V C P Pearson Copyright © 2023 Pearson Education Inc. All rights reserved. Terms of Use | Privacy Policy | Permissions 1 Contact Us |The difference in electric potential between a thunder cloud and the ground is 2.13 108 V. Electrons move from the ground which is at a lower potential to the cloud which is at a higher potential. Determine the change in electric potential energy of one of the electrons that move to the cloud.
- A potential difference exists between the inner and outer surfaces of the membrane of a cell. The inner surface is negative relative to the outer surface. If 1.25 x 10^-20 J of work is required to eject a positive sodium ion (Na+) from the interior of the cell, what is the magnitude of the potential difference between the inner and outer surfaces of the cell?A moving particle encounters an external electric field that decreases its kinetic energy from 9930 eV to 8130 eV as the particle moves from position A to position B. The electric potential at A is -59.0 V, and that at B is +13.0 V. Determine the charge of the particle. Include the algebraic sign (+ or -) with your answer. Number i Textbook and Medi Units Lower potential Higher potential VBA potential difference of 75 mV exists between the inner and outer surfaces of a cell membrane. The inner surface is negative relative to the outer surface. How much work is required to eject a positive sodium ion (Na+) from the interior of the cell?
- A proton is released from rest at point B, where the potential is 0 V. -100 V OV +100 V A B Afterward, the proton will do one of the following: a) Remains at rest at B. b) Moves toward A with constant speed. c) Moves toward A with an increasing speed. d) Moves toward C with increasing speed. e) Moves toward C with constant speed.Find the value of the electric potential at point P in the diagram below a. 360 volts b. 285 volts c. 200 volts d. 133 volts e. 102 voltsA moving particle encounters an external electric field that decreases its kinetic energy from 9790 ev to 6720 eV as the particle moves from position A to position B. The electric potential at A is -59.0 V. and that at B is +14.0 V.Determine the charge of the particle. Include the algebraic sign (+ or-) with your answer. Higher potential Lower potential Number Units