The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a = 13.0 V and b = -6.30 V/m. (a) Determine the potential at x = 0. Determine the potential at x = 3.00 m. Determine the potential at x = 6.00 m. (b) Determine the magnitude and direction of the electric field at x = 0. V/m magnitude direction ---Select--- Determine the magnitude and direction of the electric field at x = 3.00 m. magnitude V/m direction ---Select--- Determine the magnitude and direction of the electric field at x = 6.00 m. magnitude V/m direction ---Select--- V

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a = 13.0 V and b = -6.30 V/m.
(a) Determine the potential at x = 0.
V
Determine the potential at x = 3.00 m.
V
Determine the potential at x = 6.00 m.
V
(b) Determine the magnitude and direction of the electric field at x = 0.
V/m
magnitude
direction ---Select---
Determine the magnitude and direction of the electric field at x = 3.00 m.
magnitude
V/m
direction ---Select--- V
Determine the magnitude and direction of the electric field at x = 6.00 m.
magnitude
V/m
direction ---Select---
Transcribed Image Text:The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a = 13.0 V and b = -6.30 V/m. (a) Determine the potential at x = 0. V Determine the potential at x = 3.00 m. V Determine the potential at x = 6.00 m. V (b) Determine the magnitude and direction of the electric field at x = 0. V/m magnitude direction ---Select--- Determine the magnitude and direction of the electric field at x = 3.00 m. magnitude V/m direction ---Select--- V Determine the magnitude and direction of the electric field at x = 6.00 m. magnitude V/m direction ---Select---
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