The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a = 11.2 V and b = -6.10 V/m. (a) Determine the potential at x = 0. V Determine the potential at x = 3.00 m. Determine the potential at x = 6.00 m. v (b) Determine the magnitude and direction of the electric field at x = 0. magnitude V/m direction --Select--- Determine the magnitude and direction of the electric field at x = 3.00 m. magnitude V/m direction ---Select--- Determine the magnitude and direction of the electric field at x = 6.00 m. magnitude V/m direction ---Select---

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### Electrical Potential and Electric Field Calculation in a Region

#### Problem Statement:
The potential in a region between \( x = 0 \) and \( x = 6.00 \) m is given by the equation \( V = a + bx \), where \( a = 11.2 \) V and \( b = -6.10 \) V/m.

#### Calculations:

**(a) Determine the potential at \( x = 0 \).**

\[ V = \_\_\_\_\_\_\_\_ \text{ V} \]

**Determine the potential at \( x = 3.00 \) m.**

\[ V = \_\_\_\_\_\_\_\_ \text{ V} \]

**Determine the potential at \( x = 6.00 \) m.**

\[ V = \_\_\_\_\_\_\_\_ \text{ V} \]

**(b) Determine the magnitude and direction of the electric field at \( x = 0 \).**

Magnitude: 

\[ \_\_\_\_\_\_\_\_ \text{ V/m} \]

Direction:

\[
\text{Select Direction:} \quad \_\_\_\_\_\_\_\_
\]

**Determine the magnitude and direction of the electric field at \( x = 3.00 \) m.**

Magnitude:

\[ \_\_\_\_\_\_\_\_ \text{ V/m} \]

Direction:

\[
\text{Select Direction:} \quad \_\_\_\_\_\_\_\_
\]

**Determine the magnitude and direction of the electric field at \( x = 6.00 \) m.**

Magnitude:

\[ \_\_\_\_\_\_\_\_ \text{ V/m} \]

Direction:

\[
\text{Select Direction:} \quad \_\_\_\_\_\_\_\_
\]

---

### Explanation of Graphs/Diagrams (if present)
*As this particular image only contains textual information in the form of questions and input fields without any graphical content, there are no graphs or diagrams to explain.*
Transcribed Image Text:### Electrical Potential and Electric Field Calculation in a Region #### Problem Statement: The potential in a region between \( x = 0 \) and \( x = 6.00 \) m is given by the equation \( V = a + bx \), where \( a = 11.2 \) V and \( b = -6.10 \) V/m. #### Calculations: **(a) Determine the potential at \( x = 0 \).** \[ V = \_\_\_\_\_\_\_\_ \text{ V} \] **Determine the potential at \( x = 3.00 \) m.** \[ V = \_\_\_\_\_\_\_\_ \text{ V} \] **Determine the potential at \( x = 6.00 \) m.** \[ V = \_\_\_\_\_\_\_\_ \text{ V} \] **(b) Determine the magnitude and direction of the electric field at \( x = 0 \).** Magnitude: \[ \_\_\_\_\_\_\_\_ \text{ V/m} \] Direction: \[ \text{Select Direction:} \quad \_\_\_\_\_\_\_\_ \] **Determine the magnitude and direction of the electric field at \( x = 3.00 \) m.** Magnitude: \[ \_\_\_\_\_\_\_\_ \text{ V/m} \] Direction: \[ \text{Select Direction:} \quad \_\_\_\_\_\_\_\_ \] **Determine the magnitude and direction of the electric field at \( x = 6.00 \) m.** Magnitude: \[ \_\_\_\_\_\_\_\_ \text{ V/m} \] Direction: \[ \text{Select Direction:} \quad \_\_\_\_\_\_\_\_ \] --- ### Explanation of Graphs/Diagrams (if present) *As this particular image only contains textual information in the form of questions and input fields without any graphical content, there are no graphs or diagrams to explain.*
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