9-14. Analyze the replacement of an old crane with$7,000 annual maintenance and a $30,000 current marketvalue with a new one for $100,000 and $2,000 annualmaintenance. The MARR is 15% per year.

use the Capital Recovery Factor (CRF) formula:CRF=i(1+i)n/(1+i)n−1Where:i=0.15 (the annual MARR of…

Answered: 9-14. Analyze the replacement of an old…

ENGR.ECONOMIC ANALYSIS

14th Edition

ISBN:9780190931919

Author:NEWNAN

Publisher:NEWNAN

Chapter1: Making Economics Decisions

Section: Chapter Questions

Problem 1QTC

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Breakeven Example 8.2 • MARR is 12% per year. Select the more economical vendor bid. -8,000 - 13.000 Initial cost. S -3,500 -1.600 Annual costs, S per year Salvage value. $ Life. vears 2,000 10
Q4. [ remaining useful life) are shown in the table below. Assume the MARR is 10% per year. Based on this information, - ] The present worth of the cash flows through year k, PWk for a defender (3- year What is the economic life and the related minimum equivalent uniform annual cost, EUAC, for the defender? a. b. Compute marginal cost, show your calculations and fill the table below. Year(k) Total (marginal) cost PWk EUAC -$14,020 -$28,100 3 -$43,075
The problem A young engineer is considering to built a 1 unit apartment near a commercial center. Because of the location, the investment can guarantee a 90% occupancy rate. So then, he projects an earning of 20% annually. Other data are the following: Land Building cost Projected Useful life Cost of land after 20 years Cost of Building after 20 years Rent/unit/month Maintenance/unit/year Property Taxes Building Insurance P10M 14M 20 years 38M 3.8M 15,000.00 2,200.00 1% 0.7% Is this a good investment? Apply the methods of economic studies.
For th below two machines and based on AW analysis which machine we should select? MARR=10% Machine A Machine B 26612 12417 4135 Life, years 3 Answer the below question: B- the AW for machine B= First cost, $ Annual cost, $/year Salvage value, $ 140454 7170 infinite
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1. You have been selected to prepare the following analysis of cost alternatives and select the preferred alternative. The study period is 10 years and the MARR=12% per year. A Capital Investment Annual Net- $11,000 $16,000 $20,000 600 900 1000 Revenues Salvage Value 1,000 1,300 2,000 Economic Life 10 yrs 10yrs 10yrs
Engineering Eco
A company is considering purchasing either machine A or B, given that MARR is 10%, and the company projected sales is 40,000 units. Machine A Machine B $90,000 $39,000 $1100 +.02xunits $600 +0.03xunits Initial cost $70,000 $40,000 $1000+0.03xunit $500+0.05xunit 8 years $15,000 Annual revenues Annual Operation cost Annual Maintenance cost 6 years $10,000 Life span Salvage value Draw the cash fiow diagram for each machine. a. b. Compute ERR for each machine, based on computed ERRS, which machine is to be selected7 Explain the difference between the IRR & ERR methods as explained in the lecture.
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CB Electronix must buy a piece of equipment to place electronic components on the printed circuit boards it assembles. The proposed equipment has a 10-year life with no scrap value. The supplier has given CB several purchase alternatives. The first is to purchase the equipment for $950,000. The second is to pay for the equipment in 10 equal installments of $125,000 each, starting one year from now. The third is to pay $210,000 now and S85,000 at the end of each year for the next 10 years. Complete parts (a) and (b) below. a. Which alternative should CB choose if its MARR is 11 percent per year? Use an IRR comparison approach. Considering the alternatives in the order of lowest first cost, the best option is the which has an incremental rate of return of %. (Type an integer or decimal rounded to two decimal places as needed. Use an approximate ERR if the IRR cannot be used.)
• Smalltown, PA currently has a $38,000/year contract with a private company to transport students to their school and back. Smalltown can buy a bus for $40,000 that will be adequate for the next 5 years. Operating and maintenance costs are estimated to be $25,000 per year. At the end of 5 years, the bus will have an estimated salvage value of $5,000. Their MARR is 10%/year. а. What is the Excel or closed form equation (along with the value of relevant parameters) to determine this investment's internal rate of return?

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9-14. Analyze the replacement of an old crane with $7,000 annual maintenance and a $30,000 current market value with a new one for $100,000 and $2,000 annual maintenance. The MARR is 15% per year.