7. A braced cut in sand is shown in the following figure. The height and width of the cut are 10 m and 8 m, respectively. (1) Draw the earth pressure envelope using Peck's apparent lateral pressure diagrams. (2) Determine the strut load at levels A, B, C. the spacing between struts is 3 m. (3) Determine the maximum moment of the soldier beam. (4) Determine the maximum moment of the wale at level B. Bearing capacity equation: q=dNFFF+qN F F F +0.57BN,F_F_F Equations and Tables: K. 1-sino' K≈ 0.95-sin o' Shape factors by De Depth factors by Hansen (1970) Beer (1970) Inclination factors by Meyerhof (1963) and Hanna and Meyerhof (1981) Fo=1+(/XN) Fo=1+0.4(1) B F=1+(-) tan L F, =1-0.4(-) Fâ = 1+ 2 tan ø'(1 − sin ø')² D½ F₁ =1 F₁ = F₁ = (1-2 F₁ = (1-2)² 90° Table 4.2 Bearing Capacity Factors $' NC Na N₁ Κ. K o(overconsolidate) o(normally consolidated) √OCR 0 5.14 1.00 0.00 I 5.38 1.09 0.07 2 5.63 1.20 0.15 3 5.90 1.31 0.24 K. = tan² (45-%) cosa-√cos a-cos² ' Ka =COS& K₁ = cos a cosa + √cos² a-cos² ' COSC = cosa + √cos a- - cos² o' cos² a-cos² ' 10 11 12 K₁ = sin² (B+) 13 sin² ẞ sin(ẞ-8)[1+ sin('+ +♂) sin(ø' − a). sin(B-8) sin(a + B) 14 2 15 456789DER45 6.19 1.43 0.34 6.49 1.57 0.45 6.81 1.72 0.57 7.16 1.88 0.71 7.53 2.06 0.86 7.92 2.25 1.03 8.35 2.47 1.22 8.80 2.71 1.44 9.28 2.97 1.69 9.81 3.26 1.97 10.37 3.59 2.29 10.98 3.94 2.65 16589822222222222 N Na N₁ 11.63 4.34 3.06 17 12.34 4.77 3.53 13.10 5.26 4.07 13.93 5.80 4.68 20 14.83 6.40 5.39 15.82 7.07 6.20 16.88 7.82 7.13 23 18.05 8.66 8.20 24 19.32 9.60 9.44 20.72 10.66 10.88 22.25 11.85 12.54 27 23.94 13.20 14.47 25.80 14.72 16.72 27.86 16.44 19.34 30 30.14 18.40 22.40 31 32.67 20.63 25.99 (continued) Kp == sin² (B-) sin ẞ sin(ẞ+6)[1- sin('+5) sin('+α) 12 Vsin(+6) sin(a+B) Table 4.2 Bearing Capacity Factors (Continued) $' N Na N₁ φ' No N₁₂ Ny 32 35.49 23.18 30.22 42 93.71 85.38 155.55 33 38.64 26.09 35.19 43 105.11 99.02 186.54 34 42.16 29.44 41.06 44 118.37 115.31 224.64 35 46.12 33.30 48.03 45 133.88 134.88 271.76 36 50.59 37.75 56.31 46 152.10 158.51 330.35 37 55.63 42.92 66.19 47 173.64 187.21 403.67 38 61.35 48.93 78.03 48 199.26 222.31 496.01 39 67.87 55.96 92.25 49 229.93 265.51 613.16 40 75.31 64.20 109.41 50 266.89 319.07 762.89 41 83.86 73.90 130.22

Principles of Geotechnical Engineering (MindTap Course List)
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ISBN:9781305970939
Author:Braja M. Das, Khaled Sobhan
Publisher:Braja M. Das, Khaled Sobhan
Chapter14: Lateral Earth Pressure: Curved Failure Surface
Section: Chapter Questions
Problem 14.15P: The cross section of a braced cut supporting a sheet pile installation in a clay soil is shown in...
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7. A braced cut in sand is shown in the following figure. The height and width of the cut are 10
m and 8 m, respectively.
(1) Draw the earth pressure envelope using Peck's apparent lateral pressure diagrams.
(2) Determine the strut load at levels A, B, C. the spacing between struts is 3 m.
(3) Determine the maximum moment of the soldier beam.
(4) Determine the maximum moment of the wale at level B.
Bearing capacity equation: q=dNFFF+qN F F F +0.57BN,F_F_F
Equations and Tables:
K. 1-sino' K≈ 0.95-sin o'
Shape factors by De
Depth factors by Hansen (1970)
Beer (1970)
Inclination factors by Meyerhof (1963)
and Hanna and Meyerhof (1981)
Fo=1+(/XN) Fo=1+0.4(1)
B
F=1+(-) tan
L
F, =1-0.4(-)
Fâ = 1+ 2 tan ø'(1 − sin ø')² D½
F₁ =1
F₁ = F₁ = (1-2
F₁ = (1-2)²
90°
Table 4.2 Bearing Capacity Factors
$'
NC
Na
N₁
Κ.
K
o(overconsolidate)
o(normally consolidated)
√OCR
0
5.14
1.00
0.00
I
5.38
1.09
0.07
2
5.63
1.20
0.15
3
5.90
1.31
0.24
K. = tan² (45-%)
cosa-√cos a-cos² '
Ka
=COS&
K₁ = cos a
cosa + √cos² a-cos² '
COSC =
cosa + √cos a-
- cos² o'
cos² a-cos² '
10
11
12
K₁ =
sin² (B+)
13
sin² ẞ sin(ẞ-8)[1+
sin('+ +♂) sin(ø' − a).
sin(B-8) sin(a + B)
14
2
15
456789DER45
6.19
1.43
0.34
6.49
1.57
0.45
6.81
1.72
0.57
7.16
1.88
0.71
7.53
2.06
0.86
7.92
2.25
1.03
8.35
2.47
1.22
8.80
2.71
1.44
9.28
2.97
1.69
9.81
3.26
1.97
10.37
3.59
2.29
10.98
3.94
2.65
16589822222222222
N
Na
N₁
11.63
4.34
3.06
17
12.34
4.77
3.53
13.10
5.26
4.07
13.93
5.80
4.68
20
14.83
6.40
5.39
15.82
7.07
6.20
16.88
7.82
7.13
23
18.05
8.66
8.20
24
19.32
9.60
9.44
20.72
10.66
10.88
22.25
11.85
12.54
27
23.94
13.20
14.47
25.80
14.72
16.72
27.86
16.44
19.34
30
30.14
18.40
22.40
31
32.67
20.63
25.99
(continued)
Kp
==
sin² (B-)
sin ẞ sin(ẞ+6)[1-
sin('+5) sin('+α) 12
Vsin(+6) sin(a+B)
Table 4.2 Bearing Capacity Factors (Continued)
$'
N
Na
N₁
φ'
No
N₁₂
Ny
32
35.49
23.18
30.22
42
93.71
85.38
155.55
33
38.64
26.09
35.19
43
105.11
99.02
186.54
34
42.16
29.44
41.06
44
118.37
115.31
224.64
35
46.12
33.30
48.03
45
133.88
134.88
271.76
36
50.59
37.75
56.31
46
152.10
158.51
330.35
37
55.63
42.92
66.19
47
173.64
187.21
403.67
38
61.35
48.93
78.03
48
199.26
222.31
496.01
39
67.87
55.96
92.25
49
229.93
265.51
613.16
40
75.31
64.20
109.41
50
266.89
319.07
762.89
41
83.86
73.90
130.22
Transcribed Image Text:7. A braced cut in sand is shown in the following figure. The height and width of the cut are 10 m and 8 m, respectively. (1) Draw the earth pressure envelope using Peck's apparent lateral pressure diagrams. (2) Determine the strut load at levels A, B, C. the spacing between struts is 3 m. (3) Determine the maximum moment of the soldier beam. (4) Determine the maximum moment of the wale at level B. Bearing capacity equation: q=dNFFF+qN F F F +0.57BN,F_F_F Equations and Tables: K. 1-sino' K≈ 0.95-sin o' Shape factors by De Depth factors by Hansen (1970) Beer (1970) Inclination factors by Meyerhof (1963) and Hanna and Meyerhof (1981) Fo=1+(/XN) Fo=1+0.4(1) B F=1+(-) tan L F, =1-0.4(-) Fâ = 1+ 2 tan ø'(1 − sin ø')² D½ F₁ =1 F₁ = F₁ = (1-2 F₁ = (1-2)² 90° Table 4.2 Bearing Capacity Factors $' NC Na N₁ Κ. K o(overconsolidate) o(normally consolidated) √OCR 0 5.14 1.00 0.00 I 5.38 1.09 0.07 2 5.63 1.20 0.15 3 5.90 1.31 0.24 K. = tan² (45-%) cosa-√cos a-cos² ' Ka =COS& K₁ = cos a cosa + √cos² a-cos² ' COSC = cosa + √cos a- - cos² o' cos² a-cos² ' 10 11 12 K₁ = sin² (B+) 13 sin² ẞ sin(ẞ-8)[1+ sin('+ +♂) sin(ø' − a). sin(B-8) sin(a + B) 14 2 15 456789DER45 6.19 1.43 0.34 6.49 1.57 0.45 6.81 1.72 0.57 7.16 1.88 0.71 7.53 2.06 0.86 7.92 2.25 1.03 8.35 2.47 1.22 8.80 2.71 1.44 9.28 2.97 1.69 9.81 3.26 1.97 10.37 3.59 2.29 10.98 3.94 2.65 16589822222222222 N Na N₁ 11.63 4.34 3.06 17 12.34 4.77 3.53 13.10 5.26 4.07 13.93 5.80 4.68 20 14.83 6.40 5.39 15.82 7.07 6.20 16.88 7.82 7.13 23 18.05 8.66 8.20 24 19.32 9.60 9.44 20.72 10.66 10.88 22.25 11.85 12.54 27 23.94 13.20 14.47 25.80 14.72 16.72 27.86 16.44 19.34 30 30.14 18.40 22.40 31 32.67 20.63 25.99 (continued) Kp == sin² (B-) sin ẞ sin(ẞ+6)[1- sin('+5) sin('+α) 12 Vsin(+6) sin(a+B) Table 4.2 Bearing Capacity Factors (Continued) $' N Na N₁ φ' No N₁₂ Ny 32 35.49 23.18 30.22 42 93.71 85.38 155.55 33 38.64 26.09 35.19 43 105.11 99.02 186.54 34 42.16 29.44 41.06 44 118.37 115.31 224.64 35 46.12 33.30 48.03 45 133.88 134.88 271.76 36 50.59 37.75 56.31 46 152.10 158.51 330.35 37 55.63 42.92 66.19 47 173.64 187.21 403.67 38 61.35 48.93 78.03 48 199.26 222.31 496.01 39 67.87 55.96 92.25 49 229.93 265.51 613.16 40 75.31 64.20 109.41 50 266.89 319.07 762.89 41 83.86 73.90 130.22
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