Situational Problem No. 4 A 1B mm x 2AC mm steel plate with a yield strength of 2AA MPa, and an ultimate strength of 4BB MPa is welded to a gusset plate. Note: Use the shear lag factor table 3AC mm P a.) What is the strength against Gross Yield? Use LRFD. b.) What is the strength against Gross Yield? Use ASD. c.) What is the strength against Net Rupture? Use LRFD d.) What is the strength against Net Rupture? Use ASD.
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- 2. A column HP 14 x 102 of A572 Gr. 55 steel has a length of 15 ft is fixed at both ends. Compute the design compressive strength for LRFD and the allowable compressive strength for ASD. (Steel section properties are provided in the next page) ASTM Designation A572 Gr. 42 Gr. 50 Gr. 55 Gr. 60⁰ Gr. 65⁰ Yield Stress (ksi) 42 50 55 60 65 Fu Tensile Stressa (ksi) 60 65 70 75 80Subject: Steel design- Bolted Steel Connection *Use NSCP 2015 formula/guide to solve this problem *Use Handwritten A plate having a width of 400 and a thickness of 20mm is to be connected to two plates with thickness of 12mm by four rivets. The allowable shear stress for the rivets is 150 MPa and for bearing is 1.35 Fy. If the yield strength and the ultimate strength is 248 MPa and 400 MPa respectively. Determine the Following: a.) Required diameter of rivets w/o exceeding the aloowable stress in the shear. b.) Required diameter of rivets w/o exceeding the allowable stress in bearing. c.) Required diameter of rivets w/o exceeding the allowable stress in tension.What is the manufacturing tensional yield strength (lbf) of grade S135 drill pipe? a. This is a trick question because drill pipe size is not provided b. The answer can’t be calculated because the length of the pipe is not given c. The yield strength is 135000 psi and is a property of the steel d. The yield strength is 135000 psi and depends on the cross-sectional area
- Subject is steel design please show all steps and provide correct solutionsFotoğraflar - Ekran Görüntüsü (10)_LI.jpg Tüm fotoğrafları görüntüle + Şuraya ekle: Z Düzenle ve Oluştur v E Paylaş The stress-strain diagram of a reinforcement steel having a cross-sectional diameter of 12 mm diameter and 100 mm gage length is determined after its tensile strength test as follows. Based on the stress- strain diagram determine the followings properties of the material (Poisson's ratio of the material is 0.32) : 600 a) Modulus of elasticity 550 500 b) Yield strength 450 c) Toughness 400 350 d) Resilience 300 e) Shear modulus 250 200 f) Bulk modulus 150 g) Ductility as described by 100 percent change in length 50 0.01 0.02 O.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1 0.11 0.12 0.13 0.14 0.15 0.16 0.17 0.18 Strain 18:12 18.01.2021 10 Stress, MPaA L 3 x 2 x ¼ is connected to a gusset plate via six bolts. The nominal diameter of the bolt is 0.25 inches, the pitch spacing is 1.75 inches, the gage spacing is 2 inches, and the thickness of the connection is (¼) inch. The yield stress is 50 Ksi and the ultimate stress is 60 Ksi. Consider section line (a-a') for the analysis. . a. What is the effective net area (Ae) of the angle section in inches2 [a-a']?(The shear lag factor is "0.80") b. What is the design tensile yielding strength in Kips for the steel member? c. What is the design tensile rupture strength in Kips for the steel member? d. What is the minimum Factor of Safety if a tensile load of 23 Kips is applied to the angle section? please make sure the answer is correct 100% I only need the final answers
- One bolt 34 in-16 UNF × 2 12 in. SAE grade 5 is subjected to a P load of 6 kip at atension joint. The initial stress is Fi = 25 kip. The stiffness of the bolt and the joint are kb = 6.50and km = 13.8 Mlbf / in, respectively.a) Determine the preload and service load stresses on the bolt. Compare them withthe minimum SAE test strength of the bolt.Calculate the steel ratio that will produce a tension-controlled failure if compressivestrength f’c = 28 MPa and steel yield strength fy the answer is 0.02167 but i don't know how to solve it please helpQ1: Choose the correct answer 1. If the control column slenderness (KL/r) for W12x72 section column equal to 47.73. The elastic critical buckling stress (F.) is a) 127.6 ksi b) 58.7 ksi c) 100 ksi 2. If the size of welding equal to 0.25" and length of weld equal to 5 then the value of ß is a) 0.8 b) 2 c) 1 3. If The tension member is a 4 in. x 3/8 in. thick rectangular bar. It is welded to a 1/2 in. thick gusset plate then the minimum size of welded is a)3/8" b) 1/2" c) none of a or b 4. If The tension member is a 4 in. x 3/8 in. thick rectangular bar. It is welded to a 1/2 in. thick gusset plate then the minimum size of welded is a)1/4" b) 7/16" c) none of a or b 5. If Fexx for used welded connector is 70 ksi then Fw is equal to b) 42 a) 18 c) 70
- Q.2: A rectangular bar is cut from an AISI 1018 Cold-Drawn flat steel. The bar is 50 mm wide by 8 mm thickness and has a 10 mm hole drilled through the centre. It is to be placed in the reversed axial loading to failure in an operating environment of 350°F. Using ASTM minimum properties, and a reliability of 95 percent, estimate the endurance limit and fatigue strength at 60 000 cycles. Taken Sut-64 kpsi at 70°F and notch sensitivity (q=0.8).PLEASE ANSWER THIS QUESTION ASAP!!!The angle L 8 x 8 x ½ in tension shown in the figure below must resist aservice dead load of 35 kips, live load of 50 kips, and a roof live load of 2kips. The steel used is A50 (Fy = 50 ksi, Fu = 65 ksi) and its welding length is 4”.Determine if the member has sufficient fracture and yield strength.