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6.58 The common lead-acid car battery produces a large burst of current, even at low temperatures, and is rechargeable. The reac- tion that occurs while recharging a "dead" battery is 2PBSO,(s) + 2H,O(1) Pb(s) + PbO,(s) + 2H,SO,(1) (a) Use AH values from Appendix B to calculate AH (b) Use the following equations to check your answer to part (a): rxn (1) Pb(s) + PbO,(s) + 2SO;(g) 2PBSO,(s) AH = -768 kJ rxn (2) SO;(g) + H,O(1) H,SO,(1) AH = -132 kJ rxn

6.58 The common lead-acid car battery produces a large burst of current, even at low temperatures, and is rechargeable. The reac- tion that occurs while recharging a "dead" battery is 2PBSO,(s) + 2H,O(1) Pb(s) + PbO,(s) + 2H,SO,(1) (a) Use AH values from Appendix B to calculate AH (b) Use the following equations to check your answer to part (a): rxn (1) Pb(s) + PbO,(s) + 2SO;(g) 2PBSO,(s) AH = -768 kJ rxn (2) SO;(g) + H,O(1) H,SO,(1) AH = -132 kJ rxn

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.61QE: When 7.11 g NH4NO3 is added to 100 mL water, the temperature of the calorimeter contents decreases...
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6.58 The common lead-acid car battery produces a large burst of current, even at low temperatures, and is rechargeable. The reac- tion that occurs while recharging a “dead" battery is 2PBSO,(s) + 2H,O(1) → (a) Use AH values from Appendix B to calculate AH (b) Use the following equations to check your answer to part (a): Pb(s) + PbO2(s) + 2H,SO,(!) rxn (1) Pb(s) + PbO,(s) + 2SO;(g) 2PBSO,(s) = -768 kJ AH AH = -132 kJ rxn (2) SO;(g) + H,O(I) H,SO,(1)
Transcribed Image Text:6.58 The common lead-acid car battery produces a large burst of current, even at low temperatures, and is rechargeable. The reac- tion that occurs while recharging a “dead" battery is 2PBSO,(s) + 2H,O(1) → (a) Use AH values from Appendix B to calculate AH (b) Use the following equations to check your answer to part (a): Pb(s) + PbO2(s) + 2H,SO,(!) rxn (1) Pb(s) + PbO,(s) + 2SO;(g) 2PBSO,(s) = -768 kJ AH AH = -132 kJ rxn (2) SO;(g) + H,O(I) H,SO,(1)
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