Use data to compute AG° at 82.0°C for the following reaction. 4FECI3(s) + 302(g) → 2FE2O3(s) + 6CI2(g) AH°t (FECI3(s)) = -399.5 kJ mol1 AH°r (Fe2O3(s)) = -824.2 kJ mol1 AS° (FeCl3(s)) = 142.3 J mol 1 K-1 AS° (Fe2O3(s)) = 87.4 J mol1 K-1 AS° (Cl2(g)) = 223.1 J mol 1 K-1 AS° (O2(g)) = 205.152 J mol1 K1 AG° = i kJ
Use data to compute AG° at 82.0°C for the following reaction. 4FECI3(s) + 302(g) → 2FE2O3(s) + 6CI2(g) AH°t (FECI3(s)) = -399.5 kJ mol1 AH°r (Fe2O3(s)) = -824.2 kJ mol1 AS° (FeCl3(s)) = 142.3 J mol 1 K-1 AS° (Fe2O3(s)) = 87.4 J mol1 K-1 AS° (Cl2(g)) = 223.1 J mol 1 K-1 AS° (O2(g)) = 205.152 J mol1 K1 AG° = i kJ
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy
Section: Chapter Questions
Problem 32PS: Using values of fH and S, calculate rG for each of the following reactions at 25 C. (a) 2 Na(s) + 2...
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![Use data to compute AG° at 82.0°C for the following reaction.
4FECI3(s) + 302(g) → 2FE203(s) + 6CI2(3)
AH°t (FeCl3(s)) = -399.5 kJ mol-1
AH°t (Fe2O3(s) = -824.2 kJ mol-1
AS° (FeCl3(s)) = 142.3 J mol 1 K-1
AS° (Fe2O3(s)) = 87.4 J mol-1 K-1
AS° (Cl2(g)) = 223.1 J mol-1 K-1
AS° (O2(g)) = 205.152 J mol-1 K1
AG° =
i
kJ
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Transcribed Image Text:Use data to compute AG° at 82.0°C for the following reaction.
4FECI3(s) + 302(g) → 2FE203(s) + 6CI2(3)
AH°t (FeCl3(s)) = -399.5 kJ mol-1
AH°t (Fe2O3(s) = -824.2 kJ mol-1
AS° (FeCl3(s)) = 142.3 J mol 1 K-1
AS° (Fe2O3(s)) = 87.4 J mol-1 K-1
AS° (Cl2(g)) = 223.1 J mol-1 K-1
AS° (O2(g)) = 205.152 J mol-1 K1
AG° =
i
kJ
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