Use AH° values of the following three reactions: 20F2 (g) → O2 (g) + 2F2 (g) AH° = -49.4 kJ 2CIF (g) + O2 (9) - → Cl₂O(g) + OF2 (9) AH° CIF3 (9) + O2 (g) → Cl₂O(g) + OF2 (g) AH° to calculate the AH° of the unknown reaction: = : +214.0 kJ = +236.2 kJ CIF (g) + F₂ (g) → CIF3 (9) AH° = ? kJ Report only the numerical part of your answer in units of kJ rounded to the tenths place.

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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to calculate the ΔH° of the unknown reaction:
        

         

Use AH values of the following three reactions:
20F2 (g) → O2 (g) + 2F2 (g) ▲Hº
2CLF (g) + O2 (g) → Cl₂O(g) + OF2 (g)
CIF3 (9) + O2 (9)
→Cl₂O(g) + OF₂2 (9)
-
-49.4 kJ
AH° =
+214.0 kJ
AH = +236.2 kJ
to calculate the AH° of the unknown reaction:
CIF (g) + F₂ (9)
→ CIF3 (g) ▲H° = ? kJ
Report only the numerical part of your answer in units of kJ rounded to the tenths place.
Transcribed Image Text:Use AH values of the following three reactions: 20F2 (g) → O2 (g) + 2F2 (g) ▲Hº 2CLF (g) + O2 (g) → Cl₂O(g) + OF2 (g) CIF3 (9) + O2 (9) →Cl₂O(g) + OF₂2 (9) - -49.4 kJ AH° = +214.0 kJ AH = +236.2 kJ to calculate the AH° of the unknown reaction: CIF (g) + F₂ (9) → CIF3 (g) ▲H° = ? kJ Report only the numerical part of your answer in units of kJ rounded to the tenths place.
Expert Solution
Step 1: List the Given Data

2 space OF subscript 2 space open parentheses straight g close parentheses rightwards arrow straight O subscript 2 space open parentheses straight g close parentheses plus 2 space straight F subscript 2 space open parentheses straight g close parentheses space space space space space space space space space space increment straight H degree equals negative 49.4 space kJ
2 space ClF space open parentheses straight g close parentheses plus straight O subscript 2 space open parentheses straight g close parentheses rightwards arrow Cl subscript 2 straight O space open parentheses straight g close parentheses plus OF subscript 2 space open parentheses straight g close parentheses space space space space space space space space space increment straight H degree equals plus 214.0 space kJ
ClF subscript 3 space open parentheses straight g close parentheses plus straight O subscript 2 space open parentheses straight g close parentheses space rightwards arrow 1 half space Cl subscript 2 straight O space open parentheses straight g close parentheses plus 3 over 2 space OF subscript 2 space open parentheses straight g close parentheses space space space increment straight H degree equals plus 236.2 space kJ

The target equation is:

ClF space open parentheses straight g close parentheses plus straight F subscript 2 space open parentheses straight g close parentheses rightwards arrow ClF subscript 3 space open parentheses straight g close parentheses

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