2. Lead (II) sulfide is the principle source of lead metal. To obtain the metal, the sulfide is first heated in air to produce PbO. ΔΗ = .415.4 kJ PbS(+3/202) PbO () The oxide is then reduced to the metal with carbon. PbO() + SO₂(g) PbO+CPb + COⓇ AH = +108.5 kJ Calculate 4H for the reaction of one mole of PbS with oxygen and carbon, forming lead, sulfur dioxide and carbon monoxide. 3. Calculate AH for the formation of one mole of N₂O, from the elements at 25°C using the following data. 2H2+O2H₂O + H₂O - N₂O5 3.0), 1/2N2(g) + 3/202(g) +2H2(g) HNO3 AH = -174.1 kJ 2HNO₂ ΔΗ = -571.6 kJ AH = -73.7 kJ →
2. Lead (II) sulfide is the principle source of lead metal. To obtain the metal, the sulfide is first heated in air to produce PbO. ΔΗ = .415.4 kJ PbS(+3/202) PbO () The oxide is then reduced to the metal with carbon. PbO() + SO₂(g) PbO+CPb + COⓇ AH = +108.5 kJ Calculate 4H for the reaction of one mole of PbS with oxygen and carbon, forming lead, sulfur dioxide and carbon monoxide. 3. Calculate AH for the formation of one mole of N₂O, from the elements at 25°C using the following data. 2H2+O2H₂O + H₂O - N₂O5 3.0), 1/2N2(g) + 3/202(g) +2H2(g) HNO3 AH = -174.1 kJ 2HNO₂ ΔΗ = -571.6 kJ AH = -73.7 kJ →
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
2
Transcribed Image Text:2. Lead (II) sulfide is the principle source of lead metal. To obtain the metal, the sulfide is first
heated in air to produce PbO.
ΔΗ = .415.4 kJ
PbS(+3/202) PbO ()
The oxide is then reduced to the metal with carbon.
PbO + C-Pb) + CO(g)
AH = +108.5 kJ
Calculate 4H for the reaction of one mole of PbS with oxygen and carbon, forming lead, sulfur
dioxide and carbon monoxide.
+ SO2(g)
3. Calculate AH for the formation of one mole of N₂O, from the elements at 25°C using the
following data.
1/2N2(5)
2H2+O2H₂O
+ H₂O
N₂0 sig
2HNO
30)
+3/2O2(g) + 2H2(g) → HNO3 AH = -174.1 kJ
-
AH = -571.6 kJ
AH = -73.7 kJ
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 3 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY