For each of the following reactions, balance the chemical equation, calculate the emf, and calculate AG at 298 K. (Use the smallest possible coefficients for H₂O(1), H+ (aq), and HO (aq). These may be zero.) (a) In basic solution Cr(OH)3(s) is oxidized to CrO 4² (aq) by ClO (aq). Cr(OH)3(s) + clo (aq) + OH(aq) → H₂0 (1) emf AG⁰ H₂O (1) emf AGO (b) In acidic solution copper(I) ion is oxidized to copper(II) ion by nitrate ion. Cu+ (aq) + NO3(aq) + H+ (aq) - Cu²+ (aq) V emf kJ AG⁰ V (c) Aqueous iodide ion is oxidized to I₂(s) by Hg₂2+ (aq). I(aq) + Hg₂²+ (aq) + kJ V kJ H+ → Cro4² (aq) 1₂(s) Hg(/) + Cl(aq) + NO(g) + H₂O(1)

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For each of the following reactions, balance the chemical equation, calculate the emf, and calculate AG at 298 K. (Use the
smallest possible coefficients for H₂O(1), H+ (aq), and HO (aq). These may be zero.)
(a) In basic solution Cr(OH)3(s) is oxidized to CrO4²- (aq) by ClO (aq).
Cr(OH)3(s) +
clo (aq) +
OH(aq) →
H₂O (1)
emf
AGº
H₂O (1)
emf
AGº
(b) In acidic solution copper(I) ion is oxidized to copper(II) ion by nitrate ion.
Cu+ (aq) +
NO3(aq) +
H+ (aq) →
Cu²+ (aq)
V
emf
kJ
AG⁰
V
2+
(c) Aqueous iodide ion is oxidized to I₂ (s) by Hg₂²+ (aq).
H+ →
I(aq) +
Hg₂2+ (aq) +
kJ
V
kJ
Cro4² (aq)
1₂(s)
Hg(1) +
Cl(aq) +
NO(g) +
H₂O(l)
Transcribed Image Text:For each of the following reactions, balance the chemical equation, calculate the emf, and calculate AG at 298 K. (Use the smallest possible coefficients for H₂O(1), H+ (aq), and HO (aq). These may be zero.) (a) In basic solution Cr(OH)3(s) is oxidized to CrO4²- (aq) by ClO (aq). Cr(OH)3(s) + clo (aq) + OH(aq) → H₂O (1) emf AGº H₂O (1) emf AGº (b) In acidic solution copper(I) ion is oxidized to copper(II) ion by nitrate ion. Cu+ (aq) + NO3(aq) + H+ (aq) → Cu²+ (aq) V emf kJ AG⁰ V 2+ (c) Aqueous iodide ion is oxidized to I₂ (s) by Hg₂²+ (aq). H+ → I(aq) + Hg₂2+ (aq) + kJ V kJ Cro4² (aq) 1₂(s) Hg(1) + Cl(aq) + NO(g) + H₂O(l)
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