(a) A student is required to construct a battery in the form of a galvanic cell using nickel (II) nitrate and cadmium (II) nitrate. Given that a 0.75 M solution of nickel (II) nitrate must be used, what concentration of cadmium nitrate is required to achieve a cell voltage of 0.12 V at 25 °C? Ni*(aq) + 2e¨ → Ni(s) E°red = - 0.40 V *(aq) + 2e → Cd(s) E°red =- 0.26 V 2.

(a) A student is required to construct a battery in the form of a galvanic cell using nickel (II) nitrate and cadmium (II) nitrate. Given that a 0.75 M solution of nickel (II) nitrate must be used, what concentration of cadmium nitrate is required to achieve a cell voltage of 0.12 V at 25 °C? Ni(aq) + 2e¨ → Ni(s) E°red = - 0.40 V (aq) + 2e → Cd(s) E°red =- 0.26 V 2.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Electrolysis

Electrolysis is defined as the process of breaking down ionic compounds into their constituent elements by passing a direct electric current through the compound in a fluid state. The cathode reduces cations, while the anode oxidizes anions. An electrolyte, electrodes, and some form of external power source are the main components required for conducting electrolysis. A partition, such as an ion-exchange membrane or a salt bridge, may also be used, but this is optional. These are primarily used to prevent the products from diffusing near the opposing electrode.

Question

(a)
A student is required to construct a battery in the form of a galvanic cell using nickel (II) nitrate
and cadmium (II) nitrate. Given that a 0.75 M solution of nickel (II) nitrate must be used, what
concentration of cadmium nitrate is required to achieve a cell voltage of 0.12 V at 25 °C?
Ni*(aq) + 2e° → Ni(s)
Cd²*(aq) + 2e → Cd(s)
E°red= - 0.40 V
E°red = - 0.26 V
2.

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