Using the Table of Standard Electrode Potentials (Appendix L, page 1251), calculate the E°cell for each of the following reactions and predict whether each redox reaction is spontaneous or non-spontaneous. 2. 3+, (a) Au(s) + NO; (aq) + 4H*(aq) → Au³*(aq) + NO(g) + 2H2O(); (b) Сu's) + 2Fe?" (ag) —> Сu?"(aq) + Fe(s) ; (c) 2Fe" (ag) + 21 (aд) —> I2(ад) + 2Fe?"(aq); 2+ (d) Zn(OH)2(s) + 4NH3(aq) → Zn(NH3)4*(aq) + 20H (aq);

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**Chem 1B**

**Chapter-17 Tutorial Worksheet**

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**Reduction Potentials of Selected Substances:**

- **PbO₂ + HSO₄⁻ + 3H⁺ + 2e⁻ → PbSO₄ + 2H₂O;**  \( \varepsilon^\circ = -1.68 \, \text{V} \)
- **MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 2H₂O;**  \( \varepsilon^\circ = 1.51 \, \text{V} \)
- **Au³⁺ + 3e⁻ → Au;**  \( \varepsilon^\circ = 1.50 \, \text{V} \)
- **Cl₂ + 2e⁻ → 2Cl⁻;**  \( \varepsilon^\circ = 1.36 \, \text{V} \)
- **Cr₂O₇²⁻ + 14H⁺ + 6e⁻ → 2Cr³⁺ + 7H₂O;**  \( \varepsilon^\circ = 1.23 \, \text{V} \)
- **MnO₄⁻ + 4H⁺ + 3e⁻ → MnO₂ + 2H₂O;**  \( \varepsilon^\circ = 1.23 \, \text{V} \)
- **O₂ + 4H⁺ + 4e⁻ → 2H₂O;**  \( \varepsilon^\circ = 1.23 \, \text{V} \)
- **Br₂ + 2e⁻ → 2Br⁻;**  \( \varepsilon^\circ = 1.09 \, \text{V} \)
- **NO₃⁻ + 4H⁺ + 3e⁻ → NO + 2H₂O;**  \( \varepsilon^\circ = 0.96 \, \text{V} \)
- **2Hg²⁺ + 2e⁻ → Hg₂²⁺;**  \( \varepsilon^\circ = 0.92 \, \text{V} \)
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Transcribed Image Text:**Chem 1B** **Chapter-17 Tutorial Worksheet** --- **Reduction Potentials of Selected Substances:** - **PbO₂ + HSO₄⁻ + 3H⁺ + 2e⁻ → PbSO₄ + 2H₂O;** \( \varepsilon^\circ = -1.68 \, \text{V} \) - **MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 2H₂O;** \( \varepsilon^\circ = 1.51 \, \text{V} \) - **Au³⁺ + 3e⁻ → Au;** \( \varepsilon^\circ = 1.50 \, \text{V} \) - **Cl₂ + 2e⁻ → 2Cl⁻;** \( \varepsilon^\circ = 1.36 \, \text{V} \) - **Cr₂O₇²⁻ + 14H⁺ + 6e⁻ → 2Cr³⁺ + 7H₂O;** \( \varepsilon^\circ = 1.23 \, \text{V} \) - **MnO₄⁻ + 4H⁺ + 3e⁻ → MnO₂ + 2H₂O;** \( \varepsilon^\circ = 1.23 \, \text{V} \) - **O₂ + 4H⁺ + 4e⁻ → 2H₂O;** \( \varepsilon^\circ = 1.23 \, \text{V} \) - **Br₂ + 2e⁻ → 2Br⁻;** \( \varepsilon^\circ = 1.09 \, \text{V} \) - **NO₃⁻ + 4H⁺ + 3e⁻ → NO + 2H₂O;** \( \varepsilon^\circ = 0.96 \, \text{V} \) - **2Hg²⁺ + 2e⁻ → Hg₂²⁺;** \( \varepsilon^\circ = 0.92 \, \text{V} \) -
**Exercise on Standard Electrode Potentials**

In this exercise, you are tasked to calculate the standard cell potential (\(E^\circ_{\text{cell}}\)) for each of the given redox reactions using the Table of Standard Electrode Potentials (refer to Appendix L, page 1251), and predict whether the reactions are spontaneous or non-spontaneous.

**Reactions:**

(a) \( \text{Au}(s) + \text{NO}_3^-(aq) + 4\text{H}^+(aq) \rightarrow \text{Au}^{3+}(aq) + \text{NO}(g) + 2\text{H}_2\text{O}(l) \)

(b) \( \text{Cu}(s) + 2\text{Fe}^{2+}(aq) \rightarrow \text{Cu}^{2+}(aq) + \text{Fe}(s) \)

(c) \( 2\text{Fe}^{3+}(aq) + 2\text{I}^-(aq) \rightarrow \text{I}_2(aq) + 2\text{Fe}^{2+}(aq) \)

(d) \( \text{Zn(OH)}_2(s) + 4\text{NH}_3(aq) \rightarrow [\text{Zn(NH}_3\text{)}_4]^{2+}(aq) + 2\text{OH}^-(aq) \)

**Instructions:**

1. Use the standard reduction potentials from the table provided to find the \(E^\circ_{\text{cell}}\) for each reaction.
2. Remember, a positive \(E^\circ_{\text{cell}}\) value indicates a spontaneous reaction, while a negative value indicates a non-spontaneous reaction.

**Analysis:**

- For each reaction, write down the two half-reactions (oxidation and reduction).
- Calculate the \(E^\circ_{\text{cell}}\) using the formula:
  
  \[ E^\circ_{\text{cell}} = E^\circ_{\text{cathode}} - E^\circ_{\text{anode}} \]

- Use the calculated potential to determine spontaneity. 

Engage with this exercise to deepen your understanding of electrochemical cells and redox reaction spontaneity.
Transcribed Image Text:**Exercise on Standard Electrode Potentials** In this exercise, you are tasked to calculate the standard cell potential (\(E^\circ_{\text{cell}}\)) for each of the given redox reactions using the Table of Standard Electrode Potentials (refer to Appendix L, page 1251), and predict whether the reactions are spontaneous or non-spontaneous. **Reactions:** (a) \( \text{Au}(s) + \text{NO}_3^-(aq) + 4\text{H}^+(aq) \rightarrow \text{Au}^{3+}(aq) + \text{NO}(g) + 2\text{H}_2\text{O}(l) \) (b) \( \text{Cu}(s) + 2\text{Fe}^{2+}(aq) \rightarrow \text{Cu}^{2+}(aq) + \text{Fe}(s) \) (c) \( 2\text{Fe}^{3+}(aq) + 2\text{I}^-(aq) \rightarrow \text{I}_2(aq) + 2\text{Fe}^{2+}(aq) \) (d) \( \text{Zn(OH)}_2(s) + 4\text{NH}_3(aq) \rightarrow [\text{Zn(NH}_3\text{)}_4]^{2+}(aq) + 2\text{OH}^-(aq) \) **Instructions:** 1. Use the standard reduction potentials from the table provided to find the \(E^\circ_{\text{cell}}\) for each reaction. 2. Remember, a positive \(E^\circ_{\text{cell}}\) value indicates a spontaneous reaction, while a negative value indicates a non-spontaneous reaction. **Analysis:** - For each reaction, write down the two half-reactions (oxidation and reduction). - Calculate the \(E^\circ_{\text{cell}}\) using the formula: \[ E^\circ_{\text{cell}} = E^\circ_{\text{cathode}} - E^\circ_{\text{anode}} \] - Use the calculated potential to determine spontaneity. Engage with this exercise to deepen your understanding of electrochemical cells and redox reaction spontaneity.
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