For each of the following reactions, balance the chemical equation, calculate the emf, and calculate AG at 298 K. (Use the smallest possible coefficients for H₂O(1), H+ (aq), and HO (aq). These may be zero.) (a) In basic solution Cr(OH)3(s) is oxidized to CrO 4² (aq) by Clo (aq). Cr(OH)3(s) + CIO (aq) + OH(aq) → emf AG emf (b) In acidic solution copper(I) ion is oxidized to copper(II) ion by nitrate ion. Cu+ (aq) + NO3(aq) + H+ (aq) → Cu2+ (aq) AG⁰ V emf AG V (c) Aqueous iodide ion is oxidized to I₂(s) by Hg₂²+ (aq). I'(aq) + Hg₂2+ (aq) + H+ → KJ V kJ Cro42 (aq) 1₂(s)[ Hg() + Cl(aq) + NO(g) + H₂0 (1) H₂0 (1) H₂O(1)

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Chapter1: Chemical Foundations
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For each of the following reactions, balance the chemical equation, calculate the emf, and calculate AG° at 298 K. (Use the smallest possible coefficients for H₂O(), H+ (aq), and HO (aq). These may be zero.)
(a) In basic solution Cr(OH)3(s) is oxidized to Cro42 (aq) by ClO (aq).
Cr(OH)3(s) +
clo (aq) +
OH(aq) →
emf
AG⁰
emf
AGº
(b) In acidic solution copper(I) ion is oxidized to copper(II) ion by nitrate ion.
Cu+ (aq) +
NO3(aq) +
H+ (aq) →
| Cu²+ (aq)|
V
emf
kJ
AGº
V
(c) Aqueous iodide ion is oxidized to I₂(s) by Hg₂²+ (aq).
I (aq) +
Hg₂²+ (aq) +
kJ
V
KJ
Cro4²-(aq) |
1₂(s)
Hg() +
Cl(aq) +
NO(g) +
H₂O(1)
H₂O(1)
H₂O(1)
Transcribed Image Text:For each of the following reactions, balance the chemical equation, calculate the emf, and calculate AG° at 298 K. (Use the smallest possible coefficients for H₂O(), H+ (aq), and HO (aq). These may be zero.) (a) In basic solution Cr(OH)3(s) is oxidized to Cro42 (aq) by ClO (aq). Cr(OH)3(s) + clo (aq) + OH(aq) → emf AG⁰ emf AGº (b) In acidic solution copper(I) ion is oxidized to copper(II) ion by nitrate ion. Cu+ (aq) + NO3(aq) + H+ (aq) → | Cu²+ (aq)| V emf kJ AGº V (c) Aqueous iodide ion is oxidized to I₂(s) by Hg₂²+ (aq). I (aq) + Hg₂²+ (aq) + kJ V KJ Cro4²-(aq) | 1₂(s) Hg() + Cl(aq) + NO(g) + H₂O(1) H₂O(1) H₂O(1)
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