For each of the following reactions, balance the chemical equation, calculate the emf, and calculate AG at 298 K. (Use the smallest possible coefficients for H₂O(1), H+ (aq), and HO (aq). These may be zero.) (a) In basic solution Cr(OH)3(s) is oxidized to CrO 4² (aq) by Clo (aq). Cr(OH)3(s) + CIO (aq) + OH(aq) → emf AG emf (b) In acidic solution copper(I) ion is oxidized to copper(II) ion by nitrate ion. Cu+ (aq) + NO3(aq) + H+ (aq) → Cu2+ (aq) AG⁰ V emf AG V (c) Aqueous iodide ion is oxidized to I₂(s) by Hg₂²+ (aq). I'(aq) + Hg₂2+ (aq) + H+ → KJ V kJ Cro42 (aq) 1₂(s)[ Hg() + Cl(aq) + NO(g) + H₂0 (1) H₂0 (1) H₂O(1)
For each of the following reactions, balance the chemical equation, calculate the emf, and calculate AG at 298 K. (Use the smallest possible coefficients for H₂O(1), H+ (aq), and HO (aq). These may be zero.) (a) In basic solution Cr(OH)3(s) is oxidized to CrO 4² (aq) by Clo (aq). Cr(OH)3(s) + CIO (aq) + OH(aq) → emf AG emf (b) In acidic solution copper(I) ion is oxidized to copper(II) ion by nitrate ion. Cu+ (aq) + NO3(aq) + H+ (aq) → Cu2+ (aq) AG⁰ V emf AG V (c) Aqueous iodide ion is oxidized to I₂(s) by Hg₂²+ (aq). I'(aq) + Hg₂2+ (aq) + H+ → KJ V kJ Cro42 (aq) 1₂(s)[ Hg() + Cl(aq) + NO(g) + H₂0 (1) H₂0 (1) H₂O(1)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![For each of the following reactions, balance the chemical equation, calculate the emf, and calculate AG° at 298 K. (Use the smallest possible coefficients for H₂O(), H+ (aq), and HO (aq). These may be zero.)
(a) In basic solution Cr(OH)3(s) is oxidized to Cro42 (aq) by ClO (aq).
Cr(OH)3(s) +
clo (aq) +
OH(aq) →
emf
AG⁰
emf
AGº
(b) In acidic solution copper(I) ion is oxidized to copper(II) ion by nitrate ion.
Cu+ (aq) +
NO3(aq) +
H+ (aq) →
| Cu²+ (aq)|
V
emf
kJ
AGº
V
(c) Aqueous iodide ion is oxidized to I₂(s) by Hg₂²+ (aq).
I (aq) +
Hg₂²+ (aq) +
kJ
V
KJ
Cro4²-(aq) |
1₂(s)
Hg() +
Cl(aq) +
NO(g) +
H₂O(1)
H₂O(1)
H₂O(1)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F86624ab7-da2a-4a5b-91b8-0bf4ad8ab366%2F101b059a-0bca-4c0e-9b9c-b2d95288cbf9%2Femrg21j_processed.png&w=3840&q=75)
Transcribed Image Text:For each of the following reactions, balance the chemical equation, calculate the emf, and calculate AG° at 298 K. (Use the smallest possible coefficients for H₂O(), H+ (aq), and HO (aq). These may be zero.)
(a) In basic solution Cr(OH)3(s) is oxidized to Cro42 (aq) by ClO (aq).
Cr(OH)3(s) +
clo (aq) +
OH(aq) →
emf
AG⁰
emf
AGº
(b) In acidic solution copper(I) ion is oxidized to copper(II) ion by nitrate ion.
Cu+ (aq) +
NO3(aq) +
H+ (aq) →
| Cu²+ (aq)|
V
emf
kJ
AGº
V
(c) Aqueous iodide ion is oxidized to I₂(s) by Hg₂²+ (aq).
I (aq) +
Hg₂²+ (aq) +
kJ
V
KJ
Cro4²-(aq) |
1₂(s)
Hg() +
Cl(aq) +
NO(g) +
H₂O(1)
H₂O(1)
H₂O(1)
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