For each of the following reactions, balance the chemical equation, calculate the emf, and calculate AG° at 298 K. (Use the smallest possible coefficients for H₂O(), H+ (aq), and HO (aq). These may be zero.) (a) In acidic solution copper(I) ion is oxidized to copper(II) ion by nitrate ion. Cu+ (aq) + NO3(aq) + H+ (aq) → Cu2+ (aq) NO(g) + emf AG⁰ emf (b) Aqueous iodide ion is oxidized to I2 (s) by Hg₂²+ (aq). I(aq) + Hg₂2+ (aq) + 1₂(s) AG⁰ V emf kJ AG⁰ V kJ (c) In basic solution Cr(OH)3(s) is oxidized to CrO42 (aq) by CIO (aq). Cr(OH)3(s) + CIO (aq) + OH(aq) → CrO4² (aq) V ← +H| kJ Hg() + H₂O(l) Cl(aq) + H₂O(l) H₂O(l)

For each of the following reactions, balance the chemical equation, calculate the emf, and calculate AG° at 298 K. (Use the smallest possible coefficients for H₂O(), H+ (aq), and HO (aq). These may be zero.) (a) In acidic solution copper(I) ion is oxidized to copper(II) ion by nitrate ion. Cu+ (aq) + NO3(aq) + H+ (aq) → Cu2+ (aq) NO(g) + emf AG⁰ emf (b) Aqueous iodide ion is oxidized to I2 (s) by Hg₂²+ (aq). I(aq) + Hg₂2+ (aq) + 1₂(s) AG⁰ V emf kJ AG⁰ V kJ (c) In basic solution Cr(OH)3(s) is oxidized to CrO42 (aq) by CIO (aq). Cr(OH)3(s) + CIO (aq) + OH(aq) → CrO4² (aq) V ← +H| kJ Hg() + H₂O(l) Cl(aq) + H₂O(l) H₂O(l)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

For each of the following reactions, balance the chemical equation, calculate the emf, and calculate AG° at 298 K. (Use the smallest possible coefficients for H₂O(/), H+ (aq), and HO (aq). These may be zero.)
(a) In acidic solution copper(I) ion is oxidized to copper(II) ion by nitrate ion.
Cu+ (aq) +
NO3(aq) +
H+ (aq) →
Cu²+ (aq)
NO(g) +
emf
AG⁰
emf
(b) Aqueous iodide ion is oxidized to I₂(s) by Hg₂2+ (aq).
I(aq) +
Hg₂²+ (aq) +
H+ →
I₂(s)
AGº
V
emf
KJ
AG⁰
V
KJ
(c) In basic solution Cr(OH)3(s) is oxidized to CrO4²- (aq) by CIO (aq).
Cr(OH)3(s) +
CIO (aq) +
OH(aq) → CrO4²- (aq)
V
Hg(/) +
kJ
H₂O(1)
Cl(aq) +
H₂O(l)
H₂O(l)

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