Use data to compute AG° at 89.0°C for the following reaction.3N2H4() + 403(g) → 6NO(g) + 6H2O(1)AH°¢ (N2H4(1)) = 50.6 kJ mol 1AH°t (O3(g)) = 142.7 kJ mol 1AH°; (NO(g)) = 91.3 kJ mol-1AH°f (H2O(1)) = -285.83 kJ mol1AS° (N2H4()) = 121.2 J mol-1 K-1AS° (O3(g)) = 238.9 J mol-1 K1AS° (NO(g)) = 210.8 J mol-1 K-1AS° (H20(1)) = 69.95 J mol-1 K-1AG°f (N2H4(1)) = 149.3 kJ mol 1AG°t (O3(g)) = 163.2 kJ mol1AG°f (NO(g)) = 87.6 kJ mol-1AG°t (H2O(1)) = -237.1 kJ mol 1%3D%3D%3DAG° = ikJ

Answered: Image /qna-images/answer/abffaaa3-7e08-43a3-b0dd-b6fadd5ed5e3.jpg

Use data to compute AG° at 89.0°C for the following reaction. 3N2H4() + 403(g) → 6NO(g) + 6H2O(1) AH°t (N2H4(1)) = 50.6 kJ mol 1 AH°t (O3(g)) = 142.7 kJ mol 1 AH°; (NO(g)) = 91.3 kJ mol-1 AH°t (H2O(1)) = -285.83 kJ mol1 AS° (N2H4(1)) = 121.2 J mol-1 K-1 AS° (O3(g)) = 238.9 J mol-1 K1 AS° (NO(g)) = 210.8 J mol-1 K-1 AS° (H2O(1)) = 69.95 J mol-1 K-1 AG°f (N2H4(1)) = 149.3 kJ mol-1 AG°† (O3(g)) = 163.2 kJ mol1 AG°† (NO(g)) = 87.6 kJ mol-1 AG°† (H2O(1)) =-237.1 kJ mol 1 %3D %3D AG° = i kJ

Use data to compute AG° at 89.0°C for the following reaction. 3N2H4() + 403(g) → 6NO(g) + 6H2O(1) AH°t (N2H4(1)) = 50.6 kJ mol 1 AH°t (O3(g)) = 142.7 kJ mol 1 AH°; (NO(g)) = 91.3 kJ mol-1 AH°t (H2O(1)) = -285.83 kJ mol1 AS° (N2H4(1)) = 121.2 J mol-1 K-1 AS° (O3(g)) = 238.9 J mol-1 K1 AS° (NO(g)) = 210.8 J mol-1 K-1 AS° (H2O(1)) = 69.95 J mol-1 K-1 AG°f (N2H4(1)) = 149.3 kJ mol-1 AG°† (O3(g)) = 163.2 kJ mol1 AG°† (NO(g)) = 87.6 kJ mol-1 AG°† (H2O(1)) =-237.1 kJ mol 1 %3D %3D AG° = i kJ

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Given the following thermochemical data at 25°C and 1 atm pressure, 3/2 02(g) + 2B(s) - B203(s); AH° = -1264 kJ; O3(g) + 2B(s) - B203(s); AH° = - 1406 kJ; determine AH° for the following reaction at 25°C and 1 atm pressure. 302(g) → 203(g) O a. +980 kJ/mol O b. -980 kJ/mol O C. -2670 kJ/mol O d. +284 kJ/mol e. -284 kJ/mol
Determine the heat of dissolution of ammonium nitrate, NH4NO3, based on the heat of formation data given below. AH°, (NH4NO3(s)) = -365 kJ/mol, AH°(NH4 (aq)) = -132 KJ/mol, AH(NO3 (aq)) = -205 kJ/mol O28 kJ 438 kJ 292 kJ Ⓒ702 kJ
SiH4 (g) + 2 O2 (g) -> SiO2 (s) + 2 H20 (l) at 25ºC; where ΔН°rxn = -1 516 kJ and ΔSºrxn = -432.8 J K-1. Above what temperature would the reaction become nonspontaneous?
A reaction has a standard free-energy change of -13.10 kJ mol-¹(-3.131 kcal mol-¹). Calculate the equilibrium constant for the reaction at 25 °C. Keq =
Using AG, Calculate the K for N2 + 3H2 → 2NH3 at 25°C • AGxn=-33.32 kJ
Example: At 25°C, calculate the AG° N₂+ 3H2 → 2NH3 • AG° N2(g) = 0 kJ/mol f • AG + H2(g) = 0 kJ/mol f • AG˚ NH 3(g) = -16.66 kJ/mol f a) 12.9 kJ b) -33.3 kJ c) -16.7 kJ d) -8.33 kJ e) Unsure sys for: AG sys =ΣnpG˚ products - Σn,G° reactants 60
Calculate AG°ran for the following reaction of white phosphorous with HCl. 2P (s) + 10HC1 (g)→ 2PCI5 (g) + 5H2 (g) AGʻfof P(s) = 0 KJ/mol AG†of HCl (g) = -95.3 KJ/mol AG°fof H2 (g) = 0 KJ/mol AGʻfof PCI5(s) = -305.0 KJ/mol
Calculate AG° and K, at 25 °C for the reaction 2 HBr(g) + Cl2(g) → 2 HCl(g) + Br,(t) Is the reaction product-favored or reactant-favored under standard conditions? Thermodynamic Data: Species G°f (kJ/mol) -53.45 HBr(g) HCl(g) -95.09 AG° = kJ/mol Kp= product-favored reactant-favored
Draw the simplest mechanism possible for the reaction below. You may need to re-draw structures to show bond lines or lone pairs. Note to advanced students: There may be more than one resonance structure for one of your products. Make sure the mechanism you draw creates the resonance structure that's shown. + но + H₂O
The standard free energy change for the reaction CH4(g)+2O2(g) -> CO2(g) + 2H2O(l) is -194.8 kcal at 25ºC and -191.82 kcal at 75ºC. Calculate the heat of reaction at 25ºC.Ans: -212.6 kcal
Calculate the AH°, AS°, and AG° at 298 K for the following reaction: (Use the values found in Thermodynamic Properties to calculate your answers for questions a and b.) Al2O3(s) + 3 C(graphite) + 3 Cl₂(g) → 2 AICI3(s) + 3 CO(g) a) ΔΗο 400-64 kJ/mol b) AS° J/K.mol c) AGO 4.0 ✔ kJ/mol (Determine from the temperature, AH and AS) (d) Is the reaction extensive at standard conditions and 298 K? O Yes O NO 4.0 76.9 -89 (e) Write the expression for K. (Format example: Kp = pHC1² / pH₂. pCl2 would be entered as K_{p} = pHCI^{2}/pH_{2} . pCl_{2}.) Help chemPad X₁X (PCO)³ (pCl₂)3 Greek (PCO)^3/(pCl_2)^3 Your answer provides a different type of equation than was expected. (f) Calculate the value of K at 298 K 2.51e-16 X (Please answer to 3 significant figures.) (g) Estimate the value of K at 600 K. 1 79e-8 Ty (Please answer to 3 significant figures)
Chem Hw need help with question 66 and question 68