6. Follow the directions from Investigation 5 for the following sequence:HUMAN GENOMIC SEQUENCE (MAP 1 > 600) SITE AND SEQUENCE ENZYMES605'-GACTATTCTACGGCGCTCCCAACGATCAAAATGTGTGCCAAAAAAAAGCAGCGAAACGCA-3'▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬3'-CTGATAAGATGOGTTGCTAGTTTTACACACGGTTTTTTTTCGTCGCTTTGCGT-5¹5-G ****|-*-++++++|+++++++++|++++|---|---CGCG5'-ACGGACGTAATTTTCATTATAATTACTCCTTATCGATCATTGGCAGTTCAGGTTGTTTGG-3¹**********|-|-▬▬▬▬-|-***÷----|-+*+---+--3¹-TGCCTGCATTAAAAGTAATATTAATGAGGAATAGCTAGTAACCGTCAAGTCCAACAAACC-5¹5'-GATTCCGTGGCGAGACGATCGTTGAAAAGTSAAAAGTCGCGCGCGCTACTAAAGCTGGCAAAATGGA-3'3'-CTAAGGCACCGCTCTGCTAGCAACTTTTC5'-AGTAAACACAGTTATTIGATTYGCGATGATTTCGACCGTTTTACCT-5'TTTGATTTTCACTTTCGTTTAAATTATTTTTAGGATCGATCGGTTT-3'************|*|*|*▬▬▬f=▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬3'-TCATTTGTGTCAATAAACTAAAAGTGAAAGCAAATTTAATAAAAATCCTAGCTAGCCAAA-5'5'-ATTTTTGACTGGTCTACTAACGTTTTTTTTTGCCTTTCGTTTTCACAGTTGGTTATCTCA-3'3'-TAAAAACTGACCAGATGATTGCAAAAAAAAACGGAAAGCAAAAGTGTCAACCAATAGAGT-5¹5'-ATTAGTGCCTTAATAGTAGAGATAAATTTGGCAAGGTAAGTAACCAAAACAAATTGTTTA-3'***********…|-|-****************3'-TAATCACGGAATTATCATCTCTATTTAAACCGTTCCATTCATTGGTTTTGTTTAACAAAT-5'5'-TTTAACAAACAGACGAACAGTGACCTCGTTTACTAACTAATGATTCTTCTATTACTTGTT-3'*************þuntfp|nn|nz|n||3'-AAATTGTTTGTCTGCTTGTCACTGGAGCAAATGATTGATTACTAAGAAGATAATGAACAA-5'5'-GCAGCGTCGAAGGGGCGAGTTA TTTACGCCATCAAGGAGGCATGGTCAACCCCCAAAAC-3'3'-CGTCGCAGCTTCCCCGCT ATTAAATGCGGTAGTTCCTCCGTACCAGTTGGGGGTTTTG-5¹************|*|*|*|*|*|*|*|*|-|5'-CCCTGGAAATTTCGAATAAATGTTAACAATTTTATATAAGAAACCAAAACATTTAATTTT-3'3'-GGGACCTTTAAAGCTTATTTACAATTGTTAAAATATATTCTTTGGTTTTGTAAATTAAAA-5¹5'-GAGTTGGGAAGTTACTCGGTAGCTGCAAAAACATCGACGATATCAAACCACAAATCAACA-3'3'-CTCAACCCTTCAATGAGCCATCGACGTTTTTGTAGCTGCTATAGTTTGGTGTTTAGTTGT-5'1203001802403003604204805406007. Please write the message you have decoded here (using single letter amino acid symbols):Lab Report DNA and BLAST 139 mentLopez Chun1 1006is Diego5. For the following DNA strand, complete the following:a. Write the complementary DNA strand below the strand.5'-A CCTA CGTTC GACGTA ACCGCAT T-3'3-T6G AT GCAAG CTGCATT GG C6TAA_5²b. Replicate the DNA strand (remember semiconservative replication).5'-AC CTA CGTTCGAC GTAA CCGCATT-3'3'-5'-3'-5'-ACCGTTCGACGTAACCGCATT-3'- 5'138 DNA and BLAST Lab Report- 3'- 5'OLDNEWNEWOLDc. Transcribe the 5' to 3'DNA to an mRNA strand (remember there is NO thymine in RNA).5'-A CCTA CGTTCGACGTA ACCG CATT-3'DNAmRNAd. Take mRNA strand and convert to amino acid (protein) using mRNA codon table (Table 4).Remember mRNA is read 5' to 3' so you will need to re-write the sequence to begin with the5'end. Start protein at the AUG sequence.mRNAProtein

This exercise is about transcription and translation. Transcription is the process in which RNA polymerase enzyme copies the template strand of DNA by adding complementary bases to it. After the mRNA is formed three nucleotides present in mRNA forms a single codon that codes for a single amino acid. Several amino acids are brought by transfer RNA according to the codes given in mRNA and are linked together by peptide bonds to form an entire protein chain in the process of translation. The complementary nucleotide sequences areÀ and T , C and G5. 5' ACC GTT CGA CGT AAC CGC ATT- 3'3' TGG CAA GCT GCA TTG GCG TAA 5'a. 5' ACC TAC GTT CGA CGT AAC CGC ATT 3' 3' TGG ATG CAA GCT GCA TTG GCG TAA 5'b. 5' ACC TAC GTT CGA CGT AAC CGC ATT 3' 3' TGG ATG CAA GCT GCA TTG GCG TAA 5'5' ACC TAC GTT CGA CGT AAC CGC ATT 3' 3' TGG ATG CAA GCT GCA TTG GCG TAA 5'c. 5' ACC TAC GTT CGA CGT AAC CGC ATT 3' mRNA-5' UGG AUG CAA GCU GCA UUG GCG UAA 3' d. mRNA-5' UGG AUG CAA GCU GCA UUG GCG UAA 3' N met - gln - ala - ala- leu - Ala- stop COne letter code -MQAALAAll the sequences are transcribed and translated correctly in the above step.