6. A lever system can allow us to lift heavy objects with less force. Consider one lever to lift a 1000-kg mass as drawn below. The lever is a large uniform steel beam with mass of 120 kg and a moment of inertia of 251 kgm² about the fixed pivot point. 0.45 m 0.25 m 1000 kg 2.70 m Fapp In this horizontal position, what applied force on the other end is needed to accelerate the 1000-kg mass upward at 1.0 m/s²? (Hint: Due to the acceleration, the tension of the hanging mass is not simply (1000kg)g. Also, the angular acceleration of the beam is not 0.) Bonus: Even though you are using substantially less force to lift the 1000-kg mass, explain how energy is still conserved.
6. A lever system can allow us to lift heavy objects with less force. Consider one lever to lift a 1000-kg mass as drawn below. The lever is a large uniform steel beam with mass of 120 kg and a moment of inertia of 251 kgm² about the fixed pivot point. 0.45 m 0.25 m 1000 kg 2.70 m Fapp In this horizontal position, what applied force on the other end is needed to accelerate the 1000-kg mass upward at 1.0 m/s²? (Hint: Due to the acceleration, the tension of the hanging mass is not simply (1000kg)g. Also, the angular acceleration of the beam is not 0.) Bonus: Even though you are using substantially less force to lift the 1000-kg mass, explain how energy is still conserved.
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter11: Angular Momentum
Section: Chapter Questions
Problem 55P: A diver off the high board imparts an initial rotation with his body fully extended before going...
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Transcribed Image Text:6. A lever system can allow us to lift heavy objects with less force. Consider one lever to lift
a 1000-kg mass as drawn below. The lever is a large uniform steel beam with mass of
120 kg and a moment of inertia of 251 kgm² about the fixed pivot point.
0.45 m
0.25 m
1000 kg
2.70 m
Fapp
In this horizontal position, what applied force on the other end is needed to accelerate
the 1000-kg mass upward at 1.0 m/s²? (Hint: Due to the acceleration, the tension of the
hanging mass is not simply (1000kg)g. Also, the angular acceleration of the beam is not
0.)
Bonus: Even though you are using substantially less force to lift the 1000-kg mass,
explain how energy is still conserved.
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