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5) A merry-go-round is rotating in the counter-clockwise direction at 0.800 radians per second. The moment of inertia of the merry-go-round (without riders) is 2150 kg-m². The radius is 2.50 meters. Two children, Jimmy and Mary, are riding on the merry-go-round. Jimmy is sitting 1.00 m from the axis of rotation and his mass is 40.0 kg. Mary is sitting at the edge (2.50 m from the axis) and her mass is 30.0 kg. You can treat each child as a point mass. a) If both of the children crawl to the center of the merry-go-round, what is the new rotation speed? b) This question refers to the same merry-go-round as in part a, except there is no one on it. There is a little bit of friction in the axle of this merry-go-round, such that it stops rotating in 3.00 minutes. If its rotation speed was initially 0.800 radians per second, what is the magnitude and direction of the torque caused by friction? (You may assume the torque is constant.)

5) A merry-go-round is rotating in the counter-clockwise direction at 0.800 radians per second. The moment of inertia of the merry-go-round (without riders) is 2150 kg-m². The radius is 2.50 meters. Two children, Jimmy and Mary, are riding on the merry-go-round. Jimmy is sitting 1.00 m from the axis of rotation and his mass is 40.0 kg. Mary is sitting at the edge (2.50 m from the axis) and her mass is 30.0 kg. You can treat each child as a point mass. a) If both of the children crawl to the center of the merry-go-round, what is the new rotation speed? b) This question refers to the same merry-go-round as in part a, except there is no one on it. There is a little bit of friction in the axle of this merry-go-round, such that it stops rotating in 3.00 minutes. If its rotation speed was initially 0.800 radians per second, what is the magnitude and direction of the torque caused by friction? (You may assume the torque is constant.)

Principles of Physics: A Calculus-Based Text
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter10: Rotational Motion
Section: Chapter Questions
Problem 63P
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Please use rotational kinematics concepts to solve the problem.

5) A merry-go-round is rotating in the counter-clockwise direction at 0.800 radians per second. The moment of inertia of the merry-go-round (without riders) is 2150 kg-m². The radius is 2.50 meters. Two children, Jimmy and Mary, are riding on the merry-go-round. Jimmy is sitting 1.00 m from the axis of rotation and his mass is 40.0 kg. Mary is sitting at the edge (2.50 m from the axis) and her mass is 30.0 kg. You can treat each child as a point mass. a) If both of the children crawl to the center of the merry-go-round, what is the new rotation speed? b) This question refers to the same merry-go-round as in part a, except there is no one on it. There is a little bit of friction in the axle of this merry-go-round, such that it stops rotating in 3.00 minutes. If its rotation speed was initially 0.800 radians per second, what is the magnitude and direction of the torque caused by friction? (You may assume the torque is constant.)
Transcribed Image Text:5) A merry-go-round is rotating in the counter-clockwise direction at 0.800 radians per second. The moment of inertia of the merry-go-round (without riders) is 2150 kg-m². The radius is 2.50 meters. Two children, Jimmy and Mary, are riding on the merry-go-round. Jimmy is sitting 1.00 m from the axis of rotation and his mass is 40.0 kg. Mary is sitting at the edge (2.50 m from the axis) and her mass is 30.0 kg. You can treat each child as a point mass. a) If both of the children crawl to the center of the merry-go-round, what is the new rotation speed? b) This question refers to the same merry-go-round as in part a, except there is no one on it. There is a little bit of friction in the axle of this merry-go-round, such that it stops rotating in 3.00 minutes. If its rotation speed was initially 0.800 radians per second, what is the magnitude and direction of the torque caused by friction? (You may assume the torque is constant.)
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