The figure below displays a straight-wire resistor connected to a battery with V=1.8 V and, hence, running some steady- state current. This resistor is actually made out of two different conductive materials as shown. The first material has the resistivity p1=4.5 × 10-8 -m and length /1=3.8 cm, the second material is characterized by p₂=8.2 × 10-8 2.m and length /2=6.1 cm. Ρι P2 41 12 What is the strength E₁ of the driving electric field inside the first material?: E₁= V/m. What is the strength E2 of the driving electric field inside the second material?: E2= V/m.

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter21: Current And Direct Current Circuits
Section: Chapter Questions
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The figure below displays a straight-wire resistor connected to a battery with V=1.8 V and, hence, running some steady-
state current. This resistor is actually made out of two different conductive materials as shown. The first material has the
resistivity p1=4.5 × 10-8 -m and length /1=3.8 cm, the second material is characterized by p₂=8.2 × 10-8 2.m and
length /2=6.1 cm.
Ρι
P2
41
12
What is the strength E₁ of the driving electric field inside the first material?:
E₁=
V/m.
What is the strength E2 of the driving electric field inside the second material?:
E2=
V/m.
Transcribed Image Text:The figure below displays a straight-wire resistor connected to a battery with V=1.8 V and, hence, running some steady- state current. This resistor is actually made out of two different conductive materials as shown. The first material has the resistivity p1=4.5 × 10-8 -m and length /1=3.8 cm, the second material is characterized by p₂=8.2 × 10-8 2.m and length /2=6.1 cm. Ρι P2 41 12 What is the strength E₁ of the driving electric field inside the first material?: E₁= V/m. What is the strength E2 of the driving electric field inside the second material?: E2= V/m.
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