Two electrons are fixed 3.88 cm apart. Another electron is shot from infinity and stops midway between the two as the figure shows. What is its initial speed? Number i Units m/s 立
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- (a) Find the potential difference VB required to stop an electron (called a slopping potential) moving with an initial speed of 2.85 107 m/s. (b) Would a proton traveling at the same speed require a greater or lesser magnitude potential difference? Explain. (c) Find a symbolic expression for the ratio of the proton stopping potential and the electron stopping potential, Vp/Ve. The answer should be in terms of the proton mass mp and electron mass me.A research Vail de Graaff generator has a 2.00-m- diameter metal sphere with a charge of 5.00 mC on it. (a) What is the potential near its surface? (b) At what distance from its center is the potential 1.00 MV? (c) An oxygen atom with three missing electrons is released near the Van de Graaff generator. What is its energy in MeV when the atom is at the distance found in part b?A research-level Van de Graaff generator has a 1.95 m diameter metal sphere with a charge of 5.25 mC on it. An oxygen atom with two missing electrons is released from rest near the Van de Graaff generator. What is its kinetic energy in MeV at the distance of 47.25m?
- Two electrons are fixed 1.70 cm apart. Another electron is shot from infinity and stops midway between the two as the figure shows. What is its initial speed?This question has to do with the diagram shown, on which I have placed an electron at the origin. The grid spacing is 1 Angstrom per small square. Now place an atomic nucleus with 13 protons on positive x-axis, at x = 4.2 Angstroms. How much work did it take you to bring this nucleus in from 1 m away? A. 53.4 eV B. 35.6 eV C. 44.5 eV D. 26.7 eVTwo square, conducting plates each contain charge of magnitude Q = 35.4 nC. The plates have side length l = 20 cm and are separated by a distance d = 40 mm. Electrons are fired at speed v throgh a tiny hole in the positive plate toward the negative plate. (Remeber that E = Q/Ep0A for parallel plates) a. what is the potential difference between the plates b. if the electrons are stopped halfway between the plates, what is their initial speed, v? c. what is teh minimum speed the electrons must have if they are to make it all the way to the negative plate?
- An electron is fired at a speed vi = 4.1 × 106 m/s and at an angle θi = 38.2° between two parallel conducting plates as shown in the figure. If s = 1.9 mm and the voltage difference between the plates is ΔV = 98.3 V, determine how close, w, the electron will get to the bottom plate. Put your answer in meters and include at 6 decimal places in your answer.The next 5 questions all have to do with the diagram shown, on which I have placed an electron at the origin. The grid spacing is 1 Angstrom per small square. Now place an atomic nucleus with 20 protons on positive x-axis, at x = 6.4 Angstroms. How much work did it take you to bring this nucleus in from 1 m away? 45.0 eV 27.0 eV 58.5 eV 36.0 eV10. Figure shows an electron gun that emits electrons at very small angel with axis. The paraxial electrons emitted from the cathode (filament) are refocused at a distance s after accelerating through a potential difference V, s is given by (Take ² = 10) :- (A) S=2₁ (C) S=, 20mV eB² 10mV eB² (B) s= 20mV eB² (D) None of these
- I have placed an electron at the origin. The grid spacing is 1 Angstrom per small square. Now place an atomic nucleus with 13 protons on positive x-axis, at x = 4.2 Angstroms. How much work did it take you to bring this nucleus in from 1 m away? 53.4 eV 35.6 eV 44.5 eV 26.7 eVAn electron is fired at a speed yo = 4.5 x 106 m/s and at an angle D + + + + + + + + Path of the electron 0 00 d X + AV = -45° halfway between two parallel conducting plates that are D = 4.0 mm apart, as in the figure below. The voltage difference between the plates is AV = 135 V. (a) Determine how close, d, the electron will get to the bottom plate. mm (b) Determine the horizontal position where the electron will strike the top plate. (Report the distance from the origin along the x-axis.) mm... Path of trajectory AV w An electron is fired at a speed v¡ = 3.4 x 106 m/s and at an angle 0; = 30.5° between two parallel conducting plates as shown in the figure. If s = 1.5 mm and the voltage difference between the plates is AV = 98 V, determine how close, w, the electron will get to the %3D %3D bottom plate. Put your answer in meters and include at 6 decimal places in your answer. Do not include units. The x-axis of the coordinate system is in the middle of the parallel plate capacitor. Round your answer to 6 decimal places.