As shown below, a sign weighing 156 N is hanging (via a wire) from a uniform 110 N beam of length L. Additionally, the beam is attached to a cable that makes an angle 0 (0 = 51°) with the beam. 0.4 L 0.9 L HAT Determine the tension in the cable and the magnitude & direction of the force the hinge (the orange circle) exerts on the beam. Cable tension = 157.64 N X Hinge force = Direction of hinge force = ° relative to the horizontal in quadrant 1 ㅁ

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
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Author:Katz, Debora M.
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Chapter14: Static Equilibrium, Elasticity, And Fracture
Section: Chapter Questions
Problem 31PQ: A wooden door 2.1 m high and 0.90 m wide is hung by two hinges 1.8 m apart. The lower hinge is 15 cm...
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As shown below, a sign weighing 156 N is hanging (via a wire) from a uniform 110 N beam of length L. Additionally, the
beam is attached to a cable that makes an angle 0 (0 = 51°) with the beam.
0.4 L
0.9 L
HAT
Determine the tension in the cable and the magnitude & direction of the
force the hinge (the orange circle) exerts on the beam.
Cable tension = 157.64 N X
Hinge force =
Direction of hinge force =
° relative to the horizontal in quadrant
1
ㅁ
Transcribed Image Text:As shown below, a sign weighing 156 N is hanging (via a wire) from a uniform 110 N beam of length L. Additionally, the beam is attached to a cable that makes an angle 0 (0 = 51°) with the beam. 0.4 L 0.9 L HAT Determine the tension in the cable and the magnitude & direction of the force the hinge (the orange circle) exerts on the beam. Cable tension = 157.64 N X Hinge force = Direction of hinge force = ° relative to the horizontal in quadrant 1 ㅁ
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