This time, V = 66.9 V; R1 = 163 Ohms; R2 = 83 Ohms; R3 = 167 Ohms; R4 = 174 Ohms; R5 = 86 Ohms; and R6 = 60 Ohms. How much power flows through resistor R5? Question 4 options: 0.897 W 0.150 W 0.598 W 0.299 W Question 5 (5 points) Saved This time, V = 99.1 V; R1 = 135 Ohms; R2 = 51 Ohms; R3 = 188 Ohms; R4 = 131 Ohms; R5 = 110 Ohms; and R6 = 89 Ohms. How much power flows through resistor R6? Question 5 options: 3.762 W 2.633 W 5.643 W 1.843 W Question 6 (5 points) Saved Imagine that you ve been invited to try out a new hoversuit , and here s how it works: Someone has set up a large flat sheet, many kilometers across, somewhere on the Earth, and they ve charged the sheet up to a uniform charge density of 1.17 x 10^-6 C/m2. You are issued a special suit that you wear, and it has controls on it which allow you to charge the suit up to any number of Coulombs (C), positive or negative, that you might want. The idea is that you can control the amount of electrical repulsion (or attraction) between the suit and the charged sheet below you. What is the strength of the electric field in the region above the charged sheet? (This is easy, since I m going to give you the formula, which is E = 2 pi k Q/A, where k is the electrical constant and Q/A is the charge density.) Question 6 options: 6.61E+04 N/C 3.31E+04 N/C 5.95E+04 N/C 9.25E+04 N/C

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter20: Electric Current, Resistance, And Ohm's Law

Section: Chapter Questions

Problem 78PE: A small office-building air conditioner operates or 408-V AC and consumes 50.0 kW. (a) What is its...

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This time, V = 66.9 V; R1 = 163 Ohms; R2 = 83 Ohms; R3 = 167 Ohms; R4 = 174 Ohms; R5 = 86 Ohms; and R6 = 60 Ohms. How much power flows through resistor R5? Question 4 options: 0.897 W 0.150 W 0.598 W 0.299 W Question 5 (5 points) Saved This time, V = 99.1 V; R1 = 135 Ohms; R2 = 51 Ohms; R3 = 188 Ohms; R4 = 131 Ohms; R5 = 110 Ohms; and R6 = 89 Ohms. How much power flows through resistor R6? Question 5 options: 3.762 W 2.633 W 5.643 W 1.843 W Question 6 (5 points) Saved Imagine that you ve been invited to try out a new hoversuit , and here s how it works: Someone has set up a large flat sheet, many kilometers across, somewhere on the Earth, and they ve charged the sheet up to a uniform charge density of 1.17 x 10^-6 C/m2. You are issued a special suit that you wear, and it has controls on it which allow you to charge the suit up to any number of Coulombs (C), positive or negative, that you might want. The idea is that you can control the amount of electrical repulsion (or attraction) between the suit and the charged sheet below you. What is the strength of the electric field in the region above the charged sheet? (This is easy, since I m going to give you the formula, which is E = 2 pi k Q/A, where k is the electrical constant and Q/A is the charge density.) Question 6 options: 6.61E+04 N/C 3.31E+04 N/C 5.95E+04 N/C 9.25E+04 N/C

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