Part ADue to a jaw injury, a patient must wear a strap (Figure 1) thatproduces a net upward force of 4.60 N on his chin. The tension isthe same throughout the strap.For help with math skills, you may want to review: Vector AdditionTo what tension must the strap be adjusted to provide the necessary upward force?Express your answer in newtons.▸ View Available Hint(s)Figure75.0°>1 of 1FΕΠΙ ΑΣΦSubmitPrevious Answers?× Incorrect; Try Again; 5 attempts remainingProvide FeedbackN

Given the figure below:Then we can createWe can solve for the Tension by getting the sum of all…

Answered: Part A Due to a jaw injury, a patient…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Part B As shown, a truss is loaded by the forces P₁ = 497 lb and P₂ = 198 lb and has the dimension a = 9.40 ft. H M B с ** FCG, FGH = a/2 a/2 P₂ Determine FCG and FGH, the magnitudes of the forces in members CG and GH, respectively, using the method of sections. Assume for your calculations that each member is in tension, and include in your response the sign of each force that you obtain by applying this assumption. Express your answers numerically in pounds to three significant figures separated by a comma. ▸ View Available Hint(s) E 195] ΑΣΦΗ 41 | vec SWED ? lb
Two masses, A and B, are connected to each end of a light vertical cord, as shown in the following figure. A constant upward force 78.0 N is applied to mass A. Starting from rest, mass B descends 10.3 m in 3.00 s The tension in the cord connecting the two masses is 32.0 N (Figure 1). Part A Find the mass of B? Express your answer with the appropriate units. HA ? Value Units %3D Figure 1 of 1 > Submit Request Answer F Part B A Find the mass of A? Express your answer with the appropriate units. B Value Units
In the example below, a lady pushes a lawn mower with a force, F , equal to 5.0N. Part A If 0 is 28° the force in Cartesian co-ordinates would be given by: O F=2.3Nâu + 4.4Nŷ O F= 4.4Nt – 2.3Nŷ O F= 2.3N – 4.4Nŷ O F=4.4Nây +2.3Nŷ
c. Four forces in a plane, act at a point O, the values and directions of the forces are being as shown in figure 2. Prove that the direction of the resultant of this force is 18.8°. Demonstrate the steps that you will take to determine the value of the magnitude of the resultant. 30 N 60 50N 30 20 N 10 N
An 8.00 kg crate sits on an inclined plane that is inclined at 33.0 above the horizontal. The coefficient of kinetic friction between the crate and the surface of the plane is 0.300. A constant horizontal force F = 28.0 N is applied to the crate (Figure 1), and the crate moves down the plane. Part A If the crate is initially at rest, find its speed 2.00s after the force is applied? Express your answer with the appropriate units. HA Value Units Figure 1 of 1> Submit Request Answer Provide Feedback F 33.0°
Pls help with the following and explain the right answer, thank you. part B. Find the direction of this force as the angle measured counterclockwise from the +x+�-axis directed horizontally to the right. Express your answer in degrees.
HELP SOLVE
Quick please.
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Part D A force is applied to a block sliding along a surface (Figure 2). The magnitude of the force is 15 N, and the horizontal component of the force is 4.5 N. At what angle (in degrees) above the horizontal is the force directed? Express your answer in degrees to two significant figures. ► View Available Hint(s) 0 = || 17 ΑΣΦ ?
14-89. When the 6-kg box reaches point A it has a speed of vA = 2 m/s. Determine the angle 0 at which it leaves the smooth circular ramp and the distance s to where it falls into the cart. Neglect friction. VA = 2 m/s 20° B 1.2 m

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