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direction of this force as the angle measured counterclockwise from the +x

direction of this force as the angle measured counterclockwise from the +x

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Pls help with the following and explain the right answer, thank you.

part B.
Find the direction of this force as the angle measured counterclockwise from the +x+�-axis directed horizontally to the right.
Express your answer in degrees.
Two electrons are each 1.60×10-10 m from a proton, as shown in (Figure 1), find the magnitude and direction of the net electrical force they will exert on the proton. Figure P / 65.0° 1 of 1 e Part B Find the direction of this force as the angle measured counterclockwise from the +x-axis directed horizontally to the right. Express your answer in degrees. ΜΠΙ ΑΣΦ 0= 53.638 Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Provide Feedback ° counterclockwise from the + direction Next >
Transcribed Image Text:Two electrons are each 1.60×10-10 m from a proton, as shown in (Figure 1), find the magnitude and direction of the net electrical force they will exert on the proton. Figure P / 65.0° 1 of 1 e Part B Find the direction of this force as the angle measured counterclockwise from the +x-axis directed horizontally to the right. Express your answer in degrees. ΜΠΙ ΑΣΦ 0= 53.638 Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Provide Feedback ° counterclockwise from the + direction Next >
Expert Solution
Step 1

Given:

Two electrons and one proton.

The distance of each electron from proton is r=1.60×10-10 m

Assume angle is measured counterclockwise from positive x-axis.

Note:

Charge on proton is qp=1.6×10-19 C

Charge on one electron is qe=-1.6×10-19 C

Find:

Magnitude and direction of net force on proton due to electrons.

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