5.4.4 The Method of SectionsLearning Goal:To apply the method of sections to find the forces in specific members of a truss.The method of sections is used to find the force in a specific member of a truss and is based on the principle that, if a body is inequilibrium, then every part of that body is also in equilibrium. When applied, the method of sections "cuts" or sections the membersof a truss and exposes their internal forces. To find the unknown internal member forces, the free-body diagram of a section is drawnand the equations of equilibrium are applied:ΣF = 0Σ F, = 0ΣMo = 0Because there are only three independent equilibrium equations, section cuts should be made such that there are not more thanthree members that have unknown forces.Part AAs shown, a truss is loaded by the forces P₁ = 497 lb and P₂ = 198 lb and has the dimension a = 9.40 ft.yHMB Ca/2a/2Determine FBc, the magnitude of the force in member BC, using themethod of sections. Assume for your calculations that each member is in tension, and include in your response the sign of eachforce that you obtain by applying this assumption.195] ΑΣΦ | 11 IvecFBC =lbs

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Learning Goal: To apply the method of sections to find the forces in specific members of a truss. The method of sections is used to find the force in a specific member of a truss and is based on the principle that, if a body is in equilibrium, then every part of that body is also in equilibrium. When applied, the method of sections "cuts" or sections the members of a truss and exposes their internal forces. To find the unknown internal member forces, the free-body diagram of a section is drawn and the equations of equilibrium are applied: ΣΜ0 - 0 Because there are only three independent equilibrium equations, section cuts should be made such that there are not more than three members that have unknown forces. Part A As shown, a truss is loaded by the forces P₁ = 497 lb and P₂ = 198 lb and has the dimension a = 9.40 ft. L. B FBC = ΣF - 0 ΣΕ, = 0 C H a/2 a/2 Determine Fc, the magnitude of the force in member BC, using the method of sections. Assume for your calculations that each member is in tension, and include in your response the sign of each force that you obtain by applying this assumption. 10] ΑΣΦ / 11 /vec ? lbs

Learning Goal: To apply the method of sections to find the forces in specific members of a truss. The method of sections is used to find the force in a specific member of a truss and is based on the principle that, if a body is in equilibrium, then every part of that body is also in equilibrium. When applied, the method of sections "cuts" or sections the members of a truss and exposes their internal forces. To find the unknown internal member forces, the free-body diagram of a section is drawn and the equations of equilibrium are applied: ΣΜ0 - 0 Because there are only three independent equilibrium equations, section cuts should be made such that there are not more than three members that have unknown forces. Part A As shown, a truss is loaded by the forces P₁ = 497 lb and P₂ = 198 lb and has the dimension a = 9.40 ft. L. B FBC = ΣF - 0 ΣΕ, = 0 C H a/2 a/2 Determine Fc, the magnitude of the force in member BC, using the method of sections. Assume for your calculations that each member is in tension, and include in your response the sign of each force that you obtain by applying this assumption. 10] ΑΣΦ / 11 /vec ? lbs

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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5.4.4 The Method of Sections
Learning Goal:
To apply the method of sections to find the forces in specific members of a truss.
The method of sections is used to find the force in a specific member of a truss and is based on the principle that, if a body is in
equilibrium, then every part of that body is also in equilibrium. When applied, the method of sections "cuts" or sections the members
of a truss and exposes their internal forces. To find the unknown internal member forces, the free-body diagram of a section is drawn
and the equations of equilibrium are applied:
ΣF = 0
Σ F, = 0
ΣMo = 0
Because there are only three independent equilibrium equations, section cuts should be made such that there are not more than
three members that have unknown forces.
Part A
As shown, a truss is loaded by the forces P₁ = 497 lb and P₂ = 198 lb and has the dimension a = 9.40 ft.
y
H
M
B C
a/2
a/2
Determine FBc, the magnitude of the force in member BC, using the
method of sections. Assume for your calculations that each member is in tension, and include in your response the sign of each
force that you obtain by applying this assumption.
195] ΑΣΦ | 11 Ivec
FBC =
lbs

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Part B
As shown, a truss is loaded by the forces P₁ = 497 lb and P₂ = 198 lb and has the dimension a = 9.40 ft.
H
M
B
с
**
FCG, FGH =
a/2
a/2
P₂
Determine FCG and FGH, the magnitudes of the forces in members CG
and GH, respectively, using the method of sections. Assume for your calculations that each member is in tension, and include in
your response the sign of each force that you obtain by applying this assumption.
Express your answers numerically in pounds to three significant figures separated by a comma.
▸ View Available Hint(s)
E
195] ΑΣΦΗ 41 | vec
SWED ?
lb

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