A brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 740 N on him. The mass of the losing player plus equipment is 88 kg, and he is accelerating at 1.8 m/s2 backward. f = 740 Nm1 = 88 kgm2 = 118 kga = 1.8 m/s2 1. What is the magnitude of the force of friction, in newtons, between the losing player's feet and the grass as he slides backwards? F1= 2. What is the magnitude of the force, in newtons, that the winning player exerts on the ground to move forward if his mass plus equipment is 118 kg? Assume the second player has the same acceleration as the first. F2=
A brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 740 N on him. The mass of the losing player plus equipment is 88 kg, and he is accelerating at 1.8 m/s2 backward. f = 740 Nm1 = 88 kgm2 = 118 kga = 1.8 m/s2 1. What is the magnitude of the force of friction, in newtons, between the losing player's feet and the grass as he slides backwards? F1= 2. What is the magnitude of the force, in newtons, that the winning player exerts on the ground to move forward if his mass plus equipment is 118 kg? Assume the second player has the same acceleration as the first. F2=
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 740 N on him. The mass of the losing player plus equipment is 88 kg, and he is accelerating at 1.8 m/s2 backward.
f = 740 N
m1 = 88 kg
m2 = 118 kg
a = 1.8 m/s2
1. What is the magnitude of the
2. What is the magnitude of the force, in newtons, that the winning player exerts on the ground to move forward if his mass plus equipment is 118 kg? Assume the second player has the same acceleration as the first. F2=
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