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- Need all awnserUse grashoffs p+q > l*s for r4 and then use trig or cosine/some to find the angleCompare the magnitudes of the equilibrant vectors measured from the experiment with those obtained from the graphical and component methods. Example: A: 200 g 60° above +x axis B: 300 g 45° above -x axis C: 400 g 30°below -x-axis A, A cos a = 1.96 N x cos 60° = 0.98 N B₂B cos b = 2.94 N x cos 135º = -2.08 N C, C cos g = 3.92 N x cos 210°= -3.39 N R₂-A, + B + C₂ = -4.49 N A, A sin a = 1.96 N x sin 60° = 1.70 N By B sin b = 2.94 N x sin 135º = 2.08 N C, C sin g = 3.92 N x sin 210° = -1.96 N Ry= Ay+ By + Cy = 1.82 N Questions: I: (a) A: 200 g along +x axis B: 100 g 45° above -x axis A₂ = A cos a = B₂ =B cos b = R₂-A₂+ B₁₂= A₂ = A sin a = B, = B sin b = R₂ = A + B₂ = R=(R₂. R₂):_ Quadrant R = √ (R₂²+R₂²) = Direction:q=tan [R, /R.] (c) A: 100 g along -y axis B: 200 g along -x axis A = A cos a = B = B cos b = R₂-A₂+ B₂ = A = A sin a = B, B sin b = R=A, +B₂ = R=(R₁, R₂): Quadrant R = √ (R₂²+R₂²) = Direction:q tan¹ [R, /R]
- 2) Which of the following pairs are NOT correctly matched? O Macro stresses - Large scale and may be developed by inhomogeneous plastic deformation Macro stresses - From external loading, by non-uniform heating O Micro-stresses - Local small-scale internal stresses which arise due to arise due to heterogeneities i.e. due to differences in elastic modulus, co-efficient of expansion O Micro-stresses - Arise due to heterogeneities i.e. due to differences in elastic modulus, co-efficient of expansionWind flows over a flat plate of length L = 25 mm and width W = 8 mm. The plate is maintained at a constant temperature of 32 °C on both sides using an electric heater generating heat at a rate of Q = 0.5 W which is dissipated to air from both sides of the plate. Consider the temperature of the wind/air as 20 °C and assume that the wind speed does not exceed 100 m/s. The properties of air at this temperature are given as; specific heat capacity Cp = 1.005 kJ/kg-K, thermal conductivity k = 0.0253 W/m-K, Density p = 1.19 kg/m³, and kinematic viscosity v = 1.522 x 10 5 m²/s.revinus (1548-1642 200 N -100 cos sin 017 F 2.sin 02+ F !. 00•-100sin 60 – 90 sin 43 (R.) +(R»} V(192.4) +(60.8) = 202N Ex ( 2): The 200 N force is a resultant of two forces, one of the forces "P" has the direction along the tine AB and the other force "Q" is on the horizontal direction, determine em. 60° ços OF F2.cos 0 2 Fi.cos 0F F2.cos 02 $ 60+Qcos(0) 1------- ------ 02
- 4.2 2%) Find the moment of force about point A as shown in Figure? A 10 m B 90° 8 m 1000 KN 20° CI need the answer as soon as possibleExpress in 4 significant figures. a)Find the x-component of the moment of F2 (in lb-ft) about O. b) Find the y-component of the moment of F2 (in lb-ft) about O. c) Find the z-component of the moment of F2 (in lb-ft) about O.