1. Write the force F in Cartesian vector form and determine the direction cosines. ANS: <519.6, 300>lb, 30°, 60°, 0° 60° F = 600 lb 20°

$ Magnitude R= Direction 8 = Three forces act on point : A = 60 N at 135°, B = and C in this diagram to the correct magnitudes and directions. When this has been done correctly the dotted vector will become solid. 50 N at -45° and, C= 75 N at 60° 2. Pick up vectors A, B and C by their tails, and move them into a tip to tail arrangement. When this has been correctly done the resultant R will appear. measured Estimate the magnitude and direction of the resultant Based on this diagram, estimate the magnitude R and direction of the resultant. from the force R using the tip-to-tail method. 1. Move the tips of forces A, B, Submit part Submit part

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Given: Two forces F, and F₂ are applied to a hook. 2 Find: The resultant force in Cartesian vector form. 30° 45° Plan: 1. Using geometry and trigonometry, write F, and F₂ in Cartesian vector form. 2. Then add the two forces (by adding x, y and z- components). F2 =800 lb F₁ = 500 lb

1- In space ,the point can be specified by position vector r wnich is given by: A:r-ix+ jy c r=ix+ jy + kz B:r=ix+ D:r=ix

B: 82

A force of 800 kN is applied at point B and is directed towards point F. The Force at D = 0 and does not apply. Determine the component of the force that acts in the direction of line BE. Write this component as a Cartesian vector. The answer is (299i-598j+199k) kN, please show in depth how to solve.

Q4: The force in the Figure acts on the hook. Express it as a Cartesian vector. F = 675N (총)(S m) 2 m FB.uB (675)(0.7936i + 0.5151j+0.3282k) O FB.uB = (675)(-0.7936i + 0.5151j-0.3282k) FB.uB = (675)(-0.7936i - 0.5151j+0.3282k) FB-uB = (675)(-0.7936i + 0.5151j+0.3282k) O

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QI) At point A, the four forces Fs, Fc, Fp and Fe act, the lines of action for these forces are given by the straight lines AB, AC, AD and AF, as shown in Figure 1. Coordinate the points are: A 3 B 2. D 4 12 cm Figure 1 The magnitudes of the forces are: F7 KN, F= 3 KN, F=9 KN and F= 13 KN. Represent this force Facting on the point 4 as a Cartesian vector and determine its direction.