2. Determine the equivalent force-moment system about point A for the loads shown on the wooden boom assembly. 2 ft 150 lbf B -2 ft2 ft 200 lbf 2 ft 30% 200 lbf 2 ft 30° 150 lbf
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- Compute the moment (positive if counterclockwise, negative if clockwise) of the 0.48-lb force about the pivot O of the wall-switch toggle. F = 0.48 lb 13° A Answer: Moi 42° 0.730" 0 lb-in.PravinbhaiCompute the moment (positive if counterclockwise, negative if clockwise) of the 0.32-lb force about the pivot O of the wall-switch toggle. F = 0.32 lb 15° Α΄ Answer: Mo = lb-in. 31° 0.800"
- Q2. Choose the correct answer from a-b-c-d. 1- Determine the magnitude and direction of the moment of the force of the movement if the force at A about point P. a- Mp = 1440 NmC b- Mp = 1440 Nm Ɔ 2 m 4 m c- Mp = 600 NmC 1315 12 d- Mp = 600 Nm 260 N 3- The refrigerator has a weight of 200 lb and a center of gravity at G. Determine the force P required to move it. Will the refrigerator tip or slip? Take H = 0.4. %3D a- P = 80 lb Slips b- P = 75 lb Tips 4 ft 1.5 ft 3 ft c- P = 75 lb Slips d- P = 80 lb Tips 3 ftGiven a 2-D force system with geometry as shown. Find the magnitude of the equivalent couple moment (Nm) acting at O if P = 532 N , Q = 306 N, and T = 483 N . Round off only on the final answer expressed in 3 decimal places. Instead of units, indicate the direction of moment: use CW if clockwise , CCW if counterclockwise.The weight of a 20 lb oven door acts vertically through point D. The door is supported by a hinge at point A and two springs are symmetrically located on each side of the door. The resultant moment about point A of the weight and spring forces is zero. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. 8 in. 12 in. 5 in. -10 in.- = Based on the values of Fobtained for a 45° and a 90°, determine the stiffness of the springs. (Round the final answer to four decimal places.) The stiffness of the springs is [ lb/in.
- The rigid pipe is subject to the following loads. Neglecting the weight of the pipe, determine the moment at O. SOLVE THE FF Vector component form of 50-lb force (ANSWER: 25.000i +0j -43.30k lb) Magnitude of the resultant force (ANSWER: 78.10 lb) Position vector of the 50-lb force from point O to its point of application on the pipe. (ANSWER: -15i -10j +12k inch) Moment at point O, in vector component form. (ANSWER: 1153.01i -829.52j +250.00k lb-in)Show all the work in a sheet of paper with FBDFind the resultant force (magnitude, direction and position) of a parallel force system. F1 = 40 lb up at 2 ft from point A; F2 = 70 lb down at 8 ft from point A; and F3 = 60 lb up at 13 ft from point A. Note: point A is the left end of the bar
- The rigid pipe is subject to the following loads. Neglecting the weight of the pipe, determine the moment at O. Vector component form of 50-lb force and magnitude of the resultant force. Position vector of the 50-lb force from point O to its point of application on the pipe and the moment at point O, in vector component form.Please help. If possible show how solution would be inputted into Mathematica.A force of magnitude P = 180 N is applied to the stationary machine handle as shown. Write the force and moment reaction at 0 as vectors. Neglect the weight of the handle assembly.