For the purposes of this question, we will make a simplifying assumption that the only muscle that participates in lifting the arm laterally in abduction is the deltoid muscle. Assume that the insertion point for the deltoid on the humerus is 10 cm from the glenohumeral joint and line of action for this muscle (and all of its components together) is 10° from horizontal when the arm is at 90° abduction (straight to the side). You can assume that person has a body mass of 80 kg. The arm is 55 cm long, and the mass of the arm is approximately 5% of total body weight. Assume that the mass of the arm acts at about 40% of the total length of the arm (on the more proximal side). 0 = 10° 10 cm 55 cm Figure 1: Position and dimensions of the arm in abduction. A) Using this information, calculate the load (N) on the glenohumeral joint when there is no weight in the hand. What is the percent body weight of this load? B) Repeat the calculation when the hand is holding a 2 kg mass. Assume that 55 cm is the distance from the glenohumeral joint to the palm of the hand (and the weight).

Elements Of Electromagnetics
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For the purposes of this question, we will make a simplifying assumption that the only muscle that participates in lifting
the arm laterally in abduction is the deltoid muscle. Assume that the insertion point for the deltoid on the humerus is
10 cm from the glenohumeral joint and line of action for this muscle (and all of its components together) is 10° from
horizontal when the arm is at 90° abduction (straight to the side). You can assume that person has a body mass of 80 kg.
The arm is 55 cm long, and the mass of the arm is approximately 5% of total body weight. Assume that the mass of the
arm acts at about 40% of the total length of the arm (on the more proximal side).
0 = 10°
10 cm
55 cm
Figure 1: Position and dimensions of the arm in abduction.
A) Using this information, calculate the load (N) on the glenohumeral joint when there is no weight in
the hand. What is the percent body weight of this load?
B) Repeat the calculation when the hand is holding a 2 kg mass. Assume that 55 cm is the distance from
the glenohumeral joint to the palm of the hand (and the weight).
Transcribed Image Text:For the purposes of this question, we will make a simplifying assumption that the only muscle that participates in lifting the arm laterally in abduction is the deltoid muscle. Assume that the insertion point for the deltoid on the humerus is 10 cm from the glenohumeral joint and line of action for this muscle (and all of its components together) is 10° from horizontal when the arm is at 90° abduction (straight to the side). You can assume that person has a body mass of 80 kg. The arm is 55 cm long, and the mass of the arm is approximately 5% of total body weight. Assume that the mass of the arm acts at about 40% of the total length of the arm (on the more proximal side). 0 = 10° 10 cm 55 cm Figure 1: Position and dimensions of the arm in abduction. A) Using this information, calculate the load (N) on the glenohumeral joint when there is no weight in the hand. What is the percent body weight of this load? B) Repeat the calculation when the hand is holding a 2 kg mass. Assume that 55 cm is the distance from the glenohumeral joint to the palm of the hand (and the weight).
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