7. Determine the moment of the couple acting on the pipe assembly. (ANS: -130j lbft) 29:9 Z 8 in. 30% 25 lb 6 in. B 25 lb A
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- Two couple forces F = 67N, F - 61N, act on the frame and given that d- 4m and 0- 28". The other length parameters are a = 4m, b- 8m, C- 12m, and e- 12m. Compute the moment by the following methods: -F, -F1 F1 a) Find the moment of each couple by using cross product and add them up. M: kị N m b) Sum up the moments of all forces component about point B resolve forces into a and y components N- mtouch & OL166% 00:27 MENG250 - Practice Assi... Not saved yet •2-77. Determine the magnitude and coordinate direction angles of F, so that the resultant of the two forces is zero. Y2 B2 a2 y 60° 15°. F= 180 N OConsider the pipe assembly in .. {30i+20j30k} N and {60i 10j 55k} N. F₁ F2 = = Part A (Mia),(Mia)y, (M₁A) z = Submit Determine the moment of force F₁ about point A. Enter the components of the moment separated by commas. Express your answers in newton-meters to three significant figures. Part B Request Answer (M2A), (M2A)y, (M₂A) z = Submit Request Answer Part C. Complete previous part(s) VE ΑΣΦ | 41 vec 0.8 m IVE ΑΣΦ Determine the moment of force F2 about point A. Enter the components of the moment separated by commas. Express your answer in newton-meters to three significant figures. vec 1.20 m 0.4 m y ↓↑ ? N.m ? N.m
- The piston of a reciprocating engine exerts a firce of 180 kN on crosshead when the crank is 35 degree (angle beta) past TDC. If the stroke of the piston is 800 mm and the length of the connecting rod is 1.65 m, find, in kN. a) the guide force FG and , b) the firce on the connecting rod Rc .hint: radius AC is 1/2 of the stroke and Angle "phi" may be solved using sine law. Draw FBDIf PCD=6000lb and PGD=1000lb (both compression), find P and Q.Problem 3. What is the moment of the 1.4 kN force along the direction of the 1.0 kN force? Express your answer as a magnitude and sketch the direction of rotation about the axis defined by the 1.0 kN force TIGBAO TK 1.0KN X 539 indi 21 150 mm 195 mm 2 4 160 mm 21% ARD 19TO 1.4 kN MEBIRT 0 DAW ITOM 00 1400
- Which of the systems are equivalent to the couple in (a)? 410N 0.6 m -03 m- 15 N 0.2 m 0.4 m 6N-m 15 N 10 N (a) (b) (c) 45N 7.5 N 6N.m 7.5 N $5N (d) (e) (f) SN SN 22.5 N -0.3 m- 3 N•m 6N•M 3N•M 22.5 N 5N-m 15N 15N (g) (h) (i)5. A person pulls on a rope with a force of 100 lbs as shown below. What is the moment about point A as a result of this pulling force? Answer: 3034 ft-lb CW 200 le 10 ft 18 ft Gin A * 40 ft SAGiven a 2-D force system with geometry as shown. Find the magnitude of the equivalent couple moment (Nm) acting at O if P = 509 N , Q = 388 N, and T = 444 N . Round off only on the final answer expressed in 3 decimal places. Instead of units, indicate the direction of moment: use CW if clockwise , CCW if counterclockwise.
- Needs Complete typed solution with 100 % accuracy.The following diagram corresponds to questions 1 to 3. A beam rests on two sharp edges as shown on the image. The beam has a length of 7,50 m and a mass of 4,25 kg. Object 1 has a mass of 1,50 kg; object 2 has a mass of 2,35 kg. Point P is 0,50 m form the center of the beam. CG 1. How much is the torque done by object 1 around point P? A. 55,2 N*m B. 7,36 N*m C. 62,5 N*m D. Object 1 doesn't exert a torque. 2. How much is the torque done by the force of gravity of the beam around point P? A. 20,8 N*m N-m ך177 .B C. 156 N*m D. 313 N*m 3. If you needed to cancel the nomal forces of the two objects, where you should place object 2? The axis of rotation is point P. A. 3,30 m from point B. 9,18 m from point P C. 5,69 m from point P D. 3,62 m from point P5.) If the resultant force (single equivalent force) of the given system is known to pass through point B, what must the magnitude of the applied moment couple M be? Report a positive answer if M must be counterclockwise and a negative answer if M must be clockwise. [Answer: M = -8600 N m] 650 N 30° M -3 m 300 N -5 m- 500 N Ka -2 m- B