9. The restriction site sequence for the restriction enzyme Sau3Al and BamHI include four identical bases, making theirsticky ends identical as shown in the figure. Let's say you have foreign DNA whose flanking regions were cut with Sau3AI.Also, you want to use a plasmid containing a BamHI restriction site.(1) Would it be possible to ligate the foreign DNA into the BamHI site of the plasmid? Explain.lison Lenharc(2) Would it be possible to cut the ligated sites with Sau3AI? What about BamHI? What problems will you expect if youuse BamHI?BamHISau3AlG-G-A-T-C-Cபர்டியC-C-T-A-G-GG-A-T-CHi-目1目C-T-A-GC-C-T-A-GC-T-A-GG-A-T-C-CE EG-A-T-C=10. An ampicillin-resistant, tetracycline-resistant plasmid, pBR322, is cut with Pstl, which cleaves within the ampiresistance gene. The cut plasmid is ligated with Pstl digested Drosophila DNA to prepare a genomic library, and trcoli K12

Name: 9. The restriction site sequence for the restriction enzyme Sau3Al an
Uploaded: 2024-03-20T06:42:41.000Z
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Description: 9. The restriction site sequence for the restriction enzyme Sau3Al and BamHI include four identical bases, making theirsticky ends identical as shown in the figure. Let's say you have foreign DNA whose flanking regions were cut with Sau3AI.Also, you

Introduction:- Restriction endonucleases are the bacterial enzymes that cuts double stranded DNA molecule after recognition of their specific recognition site (restriction site). Restriction enzymes can make two types of cut, either staggered cut or blunt cut. In case of the staggered cut, formation of sticky or cohesive ends takes place. Blunt cut leads to the formation of blunt ends. The examples of restriction endonuclease enzymes are - EcoR1, Pvu1 and BamH1.Answer:-1) yes, it would be possible to ligate the foreign DNA into the BamH1 site of plasmid because the sequence generated by Sau3A1 digestion contains the complementary sequence present on plasmid strand and these sequences are ligated with the help of enzyme DNA ligase easily. BamH1 and Sau3A1 enzymes are iso-caudomers that produces same cohesive ends. 2) yes, it would be possible to cut the ligated sites with Sau3A1 because the ligated sequence contains the restriction sites with sequence: -G-A-T-C- but the ligated sequence doesn't contains the restriction sites for BamH1 because BamH1 cuts on: -C-G-A-T-C-C. But the ligated sequence will be: -C-G-A-T-C- which doesn't form palindromic sequence and hence BamH1 cutting is not possible .Explanation:- Restriction enzyme BamH1 cleaves double strand of DNA at a restriction sites containing 6 base pair sequence *-G-G-A-T-C-C-* which is an palindromic sequence but the ligated sequence that is formed in the reaction will be : *-G-G-A-T-C-*, this is a sequence of 5 base pairs containing restriction sequence for Sau3A1 which is of 4 base pairs *-G-A-T-C-* . That's why only Sau3A1 can cut the ligated sequence but BamH1 cutting is not possible