5. The alkylation of 1,4-dimethoxybenzene is shown below. OCH3 OCH3 C(CH3)3 18 M H2SO4 + (CH3)3 COH HOAc solvent t-butanol d = 0.775 g/mL (H3C)3C 74.12 g/mol OCH3 OCH3 250.38 g/mol 1,4-dimethoxybenzene 138.16 g/mol DMB If you started with 200 mg of 1,4-dimethoxybenzene and 0.45 mL of t-butanol, what would be the theoretical yield (in mg) of the dialkylated product?

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5. The alkylation of 1,4-dimethoxybenzene is shown below.
OCH3
OCH3
C(CH3)3
18 M H2SO4
+
(CH3)3 COH
HOAc solvent
t-butanol
d = 0.775 g/mL
(H3C)3C
74.12 g/mol
OCH3
OCH3
250.38 g/mol
1,4-dimethoxybenzene
138.16 g/mol
DMB
If you started with 200 mg of 1,4-dimethoxybenzene and 0.45 mL of t-butanol, what would be the
theoretical yield (in mg) of the dialkylated product?
Transcribed Image Text:5. The alkylation of 1,4-dimethoxybenzene is shown below. OCH3 OCH3 C(CH3)3 18 M H2SO4 + (CH3)3 COH HOAc solvent t-butanol d = 0.775 g/mL (H3C)3C 74.12 g/mol OCH3 OCH3 250.38 g/mol 1,4-dimethoxybenzene 138.16 g/mol DMB If you started with 200 mg of 1,4-dimethoxybenzene and 0.45 mL of t-butanol, what would be the theoretical yield (in mg) of the dialkylated product?
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