6. Use the data from the questions above to complete the chi-square analysis table below. e (o-e) (o-e)² (o-e)2 e 7. Calculate the chi-square statistic: x². x²=Σ (o-e)²= e 5. Now assume that homozygous recessive individuals never survive. You observe that over the next 5 generations, the genotypic frequencies in the population are: # of aa individuals # of Aa individuals # of AA individuals Generation 1 500 415 85 Generation 2 250 250 500 Generation 3 62 188 750 Generation 4 47 173 780 Generation 5 43 157 800
6. Use the data from the questions above to complete the chi-square analysis table below. e (o-e) (o-e)² (o-e)2 e 7. Calculate the chi-square statistic: x². x²=Σ (o-e)²= e 5. Now assume that homozygous recessive individuals never survive. You observe that over the next 5 generations, the genotypic frequencies in the population are: # of aa individuals # of Aa individuals # of AA individuals Generation 1 500 415 85 Generation 2 250 250 500 Generation 3 62 188 750 Generation 4 47 173 780 Generation 5 43 157 800
Biology: The Unity and Diversity of Life (MindTap Course List)
15th Edition
ISBN:9781337408332
Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr
Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr
Chapter14: Chromosomes And Human Inheritance
Section: Chapter Questions
Problem 4SQ
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Sickle cell anemia is homozygous recessive (aa).
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