6. Use the data from the questions above to complete the chi-square analysis table below. e (o-e) (o-e)² (o-e)2 e 7. Calculate the chi-square statistic: x². x²=Σ (o-e)²= e 5. Now assume that homozygous recessive individuals never survive. You observe that over the next 5 generations, the genotypic frequencies in the population are: # of aa individuals # of Aa individuals # of AA individuals Generation 1 500 415 85 Generation 2 250 250 500 Generation 3 62 188 750 Generation 4 47 173 780 Generation 5 43 157 800

6. Use the data from the questions above to complete the chi-square analysis table below. e (o-e) (o-e)² (o-e)2 e 7. Calculate the chi-square statistic: x². x²=Σ (o-e)²= e 5. Now assume that homozygous recessive individuals never survive. You observe that over the next 5 generations, the genotypic frequencies in the population are: # of aa individuals # of Aa individuals # of AA individuals Generation 1 500 415 85 Generation 2 250 250 500 Generation 3 62 188 750 Generation 4 47 173 780 Generation 5 43 157 800

Biology: The Unity and Diversity of Life (MindTap Course List)

14th Edition

ISBN:9781305073951

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter13: Observing Patterns In Inherited Traits

Section: Chapter Questions

Problem 4GP

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2. The following questions refer to the pedigree chart in the figure for a family, some of whose members exhibit the dominant trait, W. Affected individuals are indicated by a dark square or circle. 2 I ww Ww 2 34 5 6 III IV 1 23 A. What is the genotype of individual II-4? B. What is the genotype of individual II-5? C. If individual II-2 and his partner have a second child, what is the probability that their second child will be a normal, unaffected male? Show your work: 3. Phenylketonuria is an inherited disease caused by a recessive autosomal allele. If a woman and her husband are both carriers, what is the probability that their first child will be a phenotypically normal female? First, draw the pedigree for this family. Then, calculate the probability (show your work): 3 4. A man who is heterozygous for PTC tasting marries a woman who is homozygous recessive. They have two children. Their oldest daughter is a taster, and their youngest boy is a non-taster. What is the probability…
22.
Some recessive alleles have such a detrimental effect that they are lethal when present in both chromosomes of a pair. Homozygous recessives cannot survive and die at some point during embryonic development. Suppose that the allele r is lethal in the homozygous rr condition. What genotypic ratios would you expect among the living offspring of the following crosses? a. RRRr b. RrRr
2. Describe the phenotype of the cats with these genotypes (If allele not specified, assume wild type): CC ss OO BB dd McMc tt ww Light brown male with choco [Choose ] Light brown male with chocolate tips ctct ss OY bb TAt A uniformly colored black cat Light grey female with dark grey mackerel stripes Black female with large white patches Dark grey with black mackerel stripes Cc SS Oo BB TATA Cream male with small white patches and orange mackerel stripes CC Ss oY bb dd tt [Choose ]
Times New... - 14 BIU 1 .|. 2 Go To next Page 2. P1 = YY = yellow rose P2 = BB = blue rose Use a Punnett square to cross the P1 and P2 generation. What will be the probability of genotype and phenotype for the offspring. This trait exhibits Incomplete Dominance. Genotype: % YY % BB % YB Phenotype: % Yellow Rose % Blue Rose % Green Rose edu gear
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