4. The rate law for the reaction H₂ (g) + I2 (g) → 2 HI (g) was determined to be rate = k [H₂] [1₂], which led to a simple single-step bimolecular mechanism where an H₂ molecule simply collided with an I2 molecule. In the 1960s, though, different teams found spectroscopic evidence for this mechanism: (1) 1₂ (g) → 21 (g) (fast) (2) H₂ (g) + I (g) → H₂I (g) (fast) (3) H₂I (g) + I (g) → 2 HI (g) (slow) Show that this mechanism is consistent with the rate law: rate = k [H₂] [1₂]. To do this, assign individual rate constants for ALL forward and reverse reactions in the mechanism (I'm guessing k₁, k-1, k2, k-2 and k3). Then show that the overall rate law from combining individual rate laws for the mechanism steps yields rate= (some combination of k's) [H₂] [1₂], and thus k = (some combination of k's). Remember that there should be no reaction intermediates in the rate law, only reactants. \
4. The rate law for the reaction H₂ (g) + I2 (g) → 2 HI (g) was determined to be rate = k [H₂] [1₂], which led to a simple single-step bimolecular mechanism where an H₂ molecule simply collided with an I2 molecule. In the 1960s, though, different teams found spectroscopic evidence for this mechanism: (1) 1₂ (g) → 21 (g) (fast) (2) H₂ (g) + I (g) → H₂I (g) (fast) (3) H₂I (g) + I (g) → 2 HI (g) (slow) Show that this mechanism is consistent with the rate law: rate = k [H₂] [1₂]. To do this, assign individual rate constants for ALL forward and reverse reactions in the mechanism (I'm guessing k₁, k-1, k2, k-2 and k3). Then show that the overall rate law from combining individual rate laws for the mechanism steps yields rate= (some combination of k's) [H₂] [1₂], and thus k = (some combination of k's). Remember that there should be no reaction intermediates in the rate law, only reactants. \
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
![4. The rate law for the reaction H₂ (g) + I₂ (g) → 2 HI (g) was determined to be
rate = k [H₂] [1₂], which led to a simple single-step bimolecular mechanism where an H₂
molecule simply collided with an I₂ molecule.
In the 1960s, though, different teams found spectroscopic evidence for this mechanism:
(1)
(2)
(3)
I₂ (g) →21 (g)
H₂(g) + I (g) → H₂I (g)
H₂I (g) + I (g) → 2 HI (g)
(fast)
(fast)
(slow)
Show that this mechanism is consistent with the rate law: rate = k [H₂] [1₂]. To do this,
assign individual rate constants for ALL forward and reverse reactions in the mechanism
(I'm guessing k₁, k-1, k2, k-2 and k3). Then show that the overall rate law from combining
individual rate laws for the mechanism steps yields
rate = (some combination of k's) [H₂] [1₂], and thus k= (some combination of k's).
Remember that there should be no reaction intermediates in the rate law, only reactants. \](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F603d5899-1291-47a0-990b-5ec94451be91%2Fdcb942be-2761-4571-a7cf-7615e06f69b9%2F0t09ebb_processed.png&w=3840&q=75)
Transcribed Image Text:4. The rate law for the reaction H₂ (g) + I₂ (g) → 2 HI (g) was determined to be
rate = k [H₂] [1₂], which led to a simple single-step bimolecular mechanism where an H₂
molecule simply collided with an I₂ molecule.
In the 1960s, though, different teams found spectroscopic evidence for this mechanism:
(1)
(2)
(3)
I₂ (g) →21 (g)
H₂(g) + I (g) → H₂I (g)
H₂I (g) + I (g) → 2 HI (g)
(fast)
(fast)
(slow)
Show that this mechanism is consistent with the rate law: rate = k [H₂] [1₂]. To do this,
assign individual rate constants for ALL forward and reverse reactions in the mechanism
(I'm guessing k₁, k-1, k2, k-2 and k3). Then show that the overall rate law from combining
individual rate laws for the mechanism steps yields
rate = (some combination of k's) [H₂] [1₂], and thus k= (some combination of k's).
Remember that there should be no reaction intermediates in the rate law, only reactants. \
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 6 steps

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you

Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning

Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education

Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning

Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning

Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education

Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning

Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education

Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning

Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY