31.)The following DNA fragment was sequenced by the Sanger method. The asteriskindicates a fluorescent label.*5'------3'-0H3'------ATTACGCAAGGACATTAGAC---5'A sample of the DNA was reacted with DNA polymerase and each of the nucleotide mixtures (in anappropriate buffer) listed below. Dideoxynucleotides (ddNTPs) were added in relatively smallamounts.Lane 1: DATP, dTTP, dCTP, dGTP, ddTTPLane 2: DATP, dTTP, dCTP, dGTP, ddCTPLane 3: DATP, DTTP, dCTP, dGTP, ddATPLane 4: DATP, dTTP, DCTP, dGTP, ddGTPThe resulting DNA was separated by electrophoresis on an agarose gel, and the fluorescent bands onthe gel were located. The band pattern resulting from nucleotide mixture 1 is shown below.Assuming that all mixtures were run on the same gel, what did the remaining lanes on the gel looklike? ( Fill in the gel below.)3ElectrophoresisIl||

ANSWER;- - The second lane will run normally as in the case of Sanger's method (complementary to cytosine in the actual strand) as ddGTP has been added along with the normal deoxyribonucleotides. There is no normal tyrosine in the third solution so the PCR will halt on the incorporation of the first ddTTP that is the first nucleotide or the shortest sequence and therefore only one strand will be synthesized containing a single nucleotide. There are no dideoxynucleotides in the fourth solution so the PCR will proceed normally and only complete DNA sequences will be produced, which is the largest one containing all the nucleotides. - In the second mixture, ddGTP will attach to the new DNA, at the complementary sites of Cytosine residues. This will give four different combinations of DNA. The third mixture will give only one band because dTTP will bind complementarily to the first Adenine nucleotide. This will cease the replication process. The fourth mixture will give the maximum size of the DNA template because it has a mixture of all four nucleotides.