3. The trp repressor is a homodimer with 107 amino acid residues per monomer. The content of protondissociable groups of each monomer is given below:Side chainpKanumber/monomerZpH 4ZpH 612.5ArginineAspartateGlutamate9.4.04.010Histidine6.02LysineTyrosine-NH3®10.069.527.01-СООН4.01(a) ( : ) The isoelectric point (pl) of the protein, i.e., the pH at which the overall electrostatic chargeon the protein E z = 0, is 5.3. Although the pKa values in the table above are only approximate valuesgenerally characteristic of residues with unhindered exposure to solvent, confirm that the overall chargeon the protein must pass through zero between pH 4 and pH 6.) Estimate what must be the average pKa value of all of the residues containing carboxylic(b) (acid groups using the H-H equation below, assuming that the pka values of the positively chargedgroups do not change from the values given in the table above:pHpKalog [base]/[acid]+DNA te

As content of proton dissociable group presented in table, here we can count the charge status of…

Answered: 3. The trp repressor is a homodimer…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Please select all answers that are TRUE about post translational modification of proteases including chymotrypsin. This process is irreversible. If the N-terminus of 16 is protonated, the oxyanion hole of chymotrypsin does not form in alpha-chymotrypsin. Trypsin cleaves chymotrypsinogen into pi-chymotrypsin. H57 is protonated until alpha-chymotrypsin is created. This process occurs in the stomach. MacBook Air V7 888 23: F4 F3 FR %
Which statement is true for the active site residues of RNase A, lysozyme, or trypsin? Select any/all answers that apply. O A. His12 (RNase A) initially acts as an acid. O B. His119 (RNase A) initially acts as an acid. O C. Glu35 (lysozyme) initially acts as an acid. O D. His57 (trypsin) initially acts as an acid. O E. Ser195 (trypsin) initially acts as an acid.
You have digested a small protein with two different proteases, each protease acting on the protein in separate reactions. These are the peptide fragments generated: Trypsin: IPVK: Ile-Pro-Val-Lys ALEL: Ala-Leu-Glu-Leu HRPGDR: His-Arg-Pro-Gly-Asp-Arg FGADAEDGAMNK: Phe-Gly-Ala-Asp-Ala-Glu-Asp-Gly-Ala-Met-Asn-Lys YLEFISECIIQVLQSK: Tyr-Leu-Glu-Phe-Ile-Ser-Glu-Cys-Ile-Ile-Gln-Val-Leu-Gln-Ser-Lys Chymotrypsin: (Reaction conditions were used to maximize cutting to the C-terminal size of F, W, and Y.) LEF: Leu-Glu-Phe IPVKY: Ile-Pro-Val-Lys-Tyr GADAEDGAMNKALEL: Gly-Ala-Asp-Ala-Glu-Asp-Gly-Ala-Met-Asn-Lys-Ala-Leu-Glu-Leu ISECIIQVLQSKHRPGDRF: Ile-Ser-Glu-Cys-Ile-Ile-Gln-Val-Leu-Gln-Ser-Lys-His-Arg-Pro-Gly-Asp-Arg-Phe I am not sure what these questions are asking.
What is the role of his 12 in the RNase-catalyzed hydrolysis of RNA, as indicated in the Figure below? 5' His 119 RNA CH₂ H H 3 O Base 1' 12' 8-H His 12 -P-0-CH₂ a Base H H O -0-P=O H OH NH It acts as a general base, abstracting a proton from the 2' hydroxyl in order to increase its nucleophilicity. It forms an H-bond with his119 in order to stabilize the transition state. It donates a proton to improve the quality of the leaving group. It works through concerted general acid-base catalysis with his119 in order to favour the products of the reaction. Two of the above are true.
nyiaial liio C cysteine stop phenylalanine serine tyrosine A leucine serine stop tryptophan arginine arginine arginine arginine leucine serine stop leucine proline histidine U histidine proline proline proline leucine C A glutamine glutamine asparagine asparagine lysine lysine aspartate aspartate glutamate glutamate leucine leucine isoleucine threonine serine isoleucine threonine serine C A arginine arginine glycine glycine glycine glycine isoleucine threonine A methionine threonine valine alanine valine alanine G A valine alanine valine alanine G What would be the sequence of amino acids based on the codons found on the following MRNA? 5' AUGCCCUAUAGGUGA3' leucine - Histidine - Arginine - Valine - Cysteine-Arginine | O Tyrosine - Glysine - Isoleucine - Serine - Methionine-Stop | O Methionine - Proline - Tyrosine - Arginine-Stop O Methionine - Proline -Proline - Valine-Stop |
1
A sample of an unknown peptide was divided into two aliquots. One aliquot was treated with trypsin and the other was treated with cyanogen bromide. Given the following sequences (N-terminal to C-terminal) of the resulting fragments, deduce the sequence of the original peptide. Trypsin treatment Asn—Tyr—Asp—Met—Phe—Ala—Arg Asp—Trp—Asn—Arg Gln—Met—Tyr—Cys—Pro—Ile—Arg Gln—Cys Cyanogen bromide treatment Tyr—Cys—Pro—Ile—Arg—Asn—Tyr—Asp—Met Asp—Trp—Asn—Arg—Gln—Met Phe—Ala—Arg—Gln—Cys
In posttranslational modification, phosphates are attached to which 3 amino acids? - tyrosine - serine - proline - lysine - threonine
2. please answer this asap
Under what conditions will the following partial diploid strain of E. coli convert chorismate to tryptophan (assume trp mutants function similarly to lac mutants)? trpR* trpP trpO* trpE* trpD* trpC* trpB* trpA*/ trpR trpP trpO° trpE trpD trpC trpB trpA ect the one BEST answer (2 oints! O never O only when tryptophan levels are low O constitutively O only when tryptophan is present O only when chorismate levels are low
Given the following diagram of how protein AWESOME1 binds to it's target DNA, describe the potential effects of each of the 5 mutations shown below. The wild-type sequence of a helix #1 is also shown in the blue box, and all the mutations are in helix #1 (see numbers for identifying particular residues). a helix #1 R(1)-V-I-L-Y-F-W-I-M-Y-F-S-H-Y-W-R(16) #1 Predict the consequence of the following mutations: 1) Arg(1) to Glu 2) Arg(1) to Ala 3) Phe(6) to lle 4) Trp(7) to Phe 5) Met(9) to Pro in

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