3.The overall result ofCH OH+ 2 NAD+O + 2 NADHglycolysis can be summarizedby the equation on the right in HO-which the glucose origins of thecarbon atoms in pyruvate arecolor coded. Decide which gly-colytic reactions are responsiblefor the indicated distribution andHO-+ 2 Pi2+ 2 ATPНоOH + 2 ADPCH3+ 2 H2OGlucosePyruvateconversion of glucose atoms into pyruvate atoms Start by numbering of carbons in Glucose-6-Pi andFructose-1,6-BisPi.

Glycolysis is oxidative metabolism of glucose molecule by formation of pyruvate which enters into…

Answered: 3. The overall result of glycolysis can…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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2. The mechanism of HMG-CoA reducatse enzyme activity involves several stages. For the catalytic reaction to proceed, another substrate known as NADPH, which acts as a reducing agent is required. The kinetics of enzyme activity with NADPH at non-limiting amounts of HMG-CoA in the absence or presence of compactin is shown below. a) Based on the description above, which of the six types of enzymes does HMG-CoA reductase belong to? b) What is the Km for the reaction with no inhibitor present? Do NOT forget the units. Answers can be expressed either as a fraction or in decimals. c) What happens the measured Km with increasing amounts of compactin? (select one) increases decreases does not change d) What happens to the measured Vmax with increasing amounts of compactin? (select one) increases decreases does not change e) Based on your answers above, what type of inhibitor is compactin relative to its effects on enzyme activity NADPH? with -60 -40 1/V, (nanomoles/min)-1 -20 0.2 0.18 0.16…
During glycogen synthesis, glucose-1P is converted into a molecule called UDPG. This reaction also cleaves uridine triphosphate (UTP) forming uridine monophosphate and pyrophosphate (PPi). Provide four reasons why UTP can be used to power this reaction (no diagrams necessary).
3. Triose-phosphate isomerase (TPI) catalyzes the movement of a single proton to interconvert dihy- droxyacetone phosphate and glyceraldehyde 3-phosphate in glycolysis and gluconeogenesis. The enzyme, a dimer of identical subunits that are 248 amino acids in humans, has no cofactors, required metal ions, or cooperativity between subunits. The enzyme is found in all tissues. The value of Kcat/KM - 9.2 x 106 sec-'M-1 is close to the rate constant expected for a diffusion-limited reaction. The mechanism of the proton transfer is illustrated in the diagram below. Glu-165 Giu-165 Glu-165 ks HR H 20,PO HO, OH His-95 His-95 His-95 (a) ing structural formulas and naming enzymes and glycolytic intermediates, the reactions of the payoff phase. Consider only anerobic glycolysis. Remember that each glucose molecule yields two mole- cules of glyceraldehyde-3-phosphate (GAP). Indicate the net yield of ATP and NADH generated through anaerobic glycolysis per glucose molecule. The reaction catalyzed by…
1. The first step in the payoff phase of glycolysis is catalyzed by the enzyme glyceraldehyde 3-phosphate dehydrogenase, an enzyme that contains a nucleophilic cysteine playing a central role in the reaction. A) In the direction of gluconeogenesis, what reaction does this enzyme catalyze? AG° = -6.3 kcal/mol for this reaction in the direction of gluconeogenesis. Based on what you know about the substrates involved, provide two chemical reasons as to why the AGO of this reaction is negative.
2. The overall result of CH,OH + 2 NAD+ + 2 NADH glycolysis can be summarized by the equation on the right in which HO the glucose origins of the carbon atoms in pyruvate are color coded. Show by writing the reactions catalyzed by aldolase and triose phosphate isomerase and num- bering the carbons why this is the fate of glucose carbon atoms in pyruvate. Indicate numbering of carbons in Glucose-6-Pi, Fructose-1,6-BisPi, enzyme products, and pyruvate. HO + 2 Pi 2 + 2 ATP > OH + 2 ADP (CH3 + 2 H20 Glucose Pyruvate
1. Cyanide, oligomycin, and 2,4-dinitrophenol are all inhibitors of oxidative phosphorylation in mitochon- dria. Provide an explanation to the following conditions regarding these potent inhibitors. (a) Explain why adding cyanide to an active in vitro suspension of mitochondria blocks ATP synthesis. What happens to the rate of ATP synthesis when 2,4-dinitrophenol is added to this mitochon- drial suspension after it was treated with cyanide? (b) Explain why the rate of oxygen consumption decreases in an in vitro suspension of mito- chondria when oligomycin is added. What happens to the rate of oxygen consumption in this oligomycin- inhibited system after adding 2,4-dinitrophenol? Explain.
Which one of the following regarding the chemistry of glycolysis & gluconeogenesis is FALSE? Reaction 6 of glycolysis catalyzed by glyceraldehyde-3-phosphate dehydrogenase involves oxidation & addition of a P; group. Reaction 3 of gluconeogenesis catalyzed by enolase involves hydration, the addition of water to a carbon-carbon double bond (C=C) to form an alcohol. Reaction 1 of gluconeogenesis catalyzed by pyruvate carboxylase involves decarboxylation. Reaction 9 of gluconeogenesis catalyzed by fructose-1,6-bisphosphatase involves dephosphorylation (phosphoester hydrolysis). Reaction 1 of glycolysis catalyzed by hexokinase involves phosphorylation (using ATP). O 0000
Describe how a) Mean Arterial Pressure, b) Maximal Oxygen Consumption, and c) Blood Flow are determined using its formula. In addition, you should explain what those factors are including cardiac output, stroke volume, heart rate, resistance, a-vO2 difference, etc. Describe how many ATPs can be generated by complete cycles of beta oxidation of free fatty acid with 20 carbons. You should indicate how many cycles of beta oxidation and Krebs cycle, and total number of products as well
1. Write out the mechanism of TIM-catalyzed reaction in the direction it goes in glycolysis. Show involved enzymatic residues.
10. The first reaction in glycolysis is the phosphorylation of glucose: Pi + Glucose → Glucose-6-phosphate This is a thermodynamically unfavorable process with AGº = +13.8 kJ/mol. In a liver cell at 37 °C the concentration of both phosphate and glucose are normally maintained at about 5 mM each. The equilibrium concentration of glucose-6-phosphate according to the above data is: A. 1.18 x107 B. 8.50 x 104 C. 4.25 x 105 D. 2.21 x 10s E. 1.38 x 108 F. 3.02 X 103 G. 6.75 x 10-6 H. 4.08 x 10 I. 9.15 x106
4. As stated in your textbook, the first two reactions in glycolysis associated with unfavorable AG° values, i.e., AG° > 0, both produce a product with high phosphoryl group transfer potential. (ATP formation is not considered here.) Compare the two reactions and describe what the driving force is for both reactions that allows glycolysis to proceed to formation of pyruvate.
2. Regarding the glycolysis metabolic pathways covered in class: A. In the EMP metabolic pathway, what chemical is catabolized to form pyruvate? (1 step away) B. There are two products of step 4 in the EMP pathway. If they were not phosphorylated, how would you describe these as monosaccharides (for example, an aldohexose and a ketopentose)? C. In the TCA Cycle, what chemical is produced by catabolism of isocitrate? (1 step away) D. Describe the major differences between primary, secondary and partial oxidation metabolism in terms of cell growth rate, (ii) oxygen consumption rate, and (iii) products formed.

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3. The overall result of glycolysis can be summarized by the equation on the right in which the glucose origins of the carbon atoms in pyruvate are color coded. Decide which gly- colytic reactions are responsible for the indicated distribution and