(3)(1 pt) If acid/base reactions are as fast as everyone says they are, why didyou have to heat under reflux in the deprotonation step?(4)(2 pts) Label the 'H-NMR provided below to assign the different signals tothe matching protons. (The numbers above the signals are theintegrations). Use letters to label the different signals/protons. The H onthe alcohol is not present in the spectra.3.0باليō (ppm)2.0-OH1.00.0

Question 3: Acid-base reactions, especially those involving deprotonation, are indeed generally very…

Answered: (3) (1 pt) If acid/base reactions are…

EBK A SMALL SCALE APPROACH TO ORGANIC L

4th Edition

ISBN:9781305446021

Author:Lampman

Publisher:Lampman

Chapter31: An Oxidation–reduction Scheme: Borneol, Camphor, Isoborneol

Section: Chapter Questions

Problem 2Q

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Sketch out the proton NMR (including multiplicity, integration, rough ppm location). Explain why the peaks are located where they are in the proton NMR. Go through every proton and explain why that region of the spectrum is with that multiplicity. pls be specific N- HN-
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Hc Ha oHe Hb -Hd i) rank the labelled protons in order of increasing pka. ") Explain your answer in Ci).
Please select the correct answer choice(s) from the following The signal at 1.4 ppm is a [s/ d/ t/ q ] and is the [ TWO METHYL GROUPS OF AN ISOPROPYL/ METHYL GROUP OF AN ETHYL/ METHYL GROUP ATTACHED TO AN AROMATIC RING ].
Which one of the following compounds (from Figure #7) produced the 'H NMR spectrum (from Figure #8) shown below? Figure #7 inte compound A compound B compound C compound D Please click here if image does not display. Figure #8 3 203938 PPM 10 9 8 7 5 4 3 2 1 8 (ppm) Please click here if image does not display. O compound A O compound D O compound C O compound B
For the 1 H NMR spectrum of acetyl salicylic acid shown below, assign each signal to the proton to which it corresponds (the COOH proton does not appear on this spectrum).
Please select the correct answer choice(s) from the following The signal at 2.3 ppm is a [s/ d/ t/ q] and is a [methyl group of an isopropyl/ methyl group of an ethyl/ methyl group attached to an aromatic ring ].
(a) Rank each proton shown below in terms of relative chemical shift in the ¹H NMR spectrum. (1 = most upfield, 3 = most downfield) (i) (iii) H JO [ Ⓒ
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draw the structure of the nmr (ethyl acetate) then circle the protons on the structures and correlate the 1H's to the resonances (peaks) on the 1H NMR spectra.
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When comparing 1H NMR spectra of benzene and methylbenzene (toluene), how to determine which spectra belongs to which compound? O Signals on 1H NMR spectra of toluene will be near 11- 12 ppm., while for benzene these signals will be near 6.5-8.0 ppm: O Both spectra will be the same O IH NMR spectra of toluene will be more intense compare to benzene one O 1H NMR spectra of benzene will have just one signal, while the one of toluene will have more than one

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