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Analyze this TLC please s:starting material R:reaction.
reduction of vanillan with sodium borohydride
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- You work in a research organization that is looking for markers of various diseases that can be used as a diagnostic for the disease. It has been reported in the past that high levels of Cu are found in the sweat of people with cystic fibrosis. One of the research projects is focused on looking for high levels of Cu in samples that can be obtained non-invasively such as saliva, sweat, hair, nails, etc. The lab will analyze large samples for Cu. What instrument would you recommend purchasing to support this work, Atomic absorption spectrophotometer or an inductively coupled plasma atomic spectrophotometer? Explain the basis for your decision.You have a 11.5 mg sample of blood that contains various proteins. Hemoglobin is the only protein in the sample containing Fe. Hemoglobin contains 3.83% by mass of a compound called heme (C₃₄H₃₂FeN₄O₄, MW = 616.49 g/mol). You find that your 11.5 mg blood sample contains 30.5 micrograms of Fe. What is the mass percent of hemoglobin in your protein sample?You have a 11.5 mg sample of blood that contains various proteins. Hemoglobin is the only protein in the sample containing Fe. Hemoglobin contains 3.83% by mass of a compound called heme (C₃₄H₃₂FeN₄O₄, MW = 616.49 g/mol). You find that your 11.5 mg blood sample contains 34.9 micrograms of Fe. What is the mass percent of hemoglobin in your protein sample? -don't prematureley round
- Catra wanted to determine the concentration of copper(II) chloride at an unknown concentration .She began by trying to determine the value of epsilon (ε) using beers law for copper(II) chloride. Catra remembered in lab when they wanted to solve for epsilon they would test the absorbance for three different concentrations of a known solution and then graph it. Catra got frustrated and asked Shera what to do next to determine epsilon. What should Shera tell Catra?For the reaction 2N2O5(g) ® 4NO2(g) + O2(g), the following data were collected. t (minutes) [N2O5] (mol/L) 0 1.24 x 10–2 10 0.92 x 10–2 20 0.68 x10–2 30 0.50 x 10–2 40 0.37 x 10–2 50 0.28 ´ 10–2 70 0.15 ´ 10–2 The initial rate of production of NO2 for this reaction is approximately: A) 6.4 x10–4 mol/L • min B) 3.2 x10–4 mol/L • min C) 1.24 x 10–2 mol/L • min D) 1.6 x 10–4 mol/L • min E) none of theseBr O
- Consider the following data concerning the equation: H2O2 + 3I– + 2H+ → I3– + 2H2O [H2O2] [I–] [H+] rate I 0.100 M 5.00 × 10–4 M 1.00 × 10–2 M 0.137 M/sec II. 0.100 M 1.00 × 10–3 M 1.00 × 10–2 M 0.268 M/sec III. 0.200 M 1.00 × 10–3 M 1.00 × 10–2 M 0.542 M/sec IV. 0.400 M 1.00 × 10–3 M 2.00 × 10–2 M 1.084 M/sec The rate law for this reaction isConsider the following data concerning the equation: H2O2 + 3I– + 2H+ → I3– + 2H2O [H2O2] [I–] [H+] rate I 0.100 M 5.00 × 10–4 M 1.00 × 10–2 M 0.137 M/sec II. 0.100 M 1.00 × 10–3 M 1.00 × 10–2 M 0.268 M/sec III. 0.200 M 1.00 × 10–3 M 1.00 × 10–2 M 0.542 M/sec IV. 0.400 M 1.00 × 10–3 M 2.00 × 10–2 M 1.084 M/sec The rate law for this reaction is a. rate = k[H2O2][I–][H+] b. rate = k[H2O2][H+] c. rate = k[H2O2]2[I–]2[H+]2 d. None of these e. rate = k[H2O2][I–] f. rate = k[I–][H+]Consider the following data concerning the equation: H2O2 + 3I– + 2H+ → I3– + 2H2O [H2O2][I–][H+]rate I 0.100 M 5.00 × 10–4 M 1.00 × 10–2 M 0.137 M/sec II. 0.100 M 1.00 × 10–3 M 1.00 × 10–2 M 0.268 M/sec III. 0.200 M 1.00 × 10–3 M 1.00 × 10–2 M 0.542 M/sec IV. 0.400 M 1.00 × 10–3 M 2.00 × 10–2 M 1.084 M/sec a. The rate law for this reaction is a. rate = k[H2O2][I–][H+] b. rate = k[H2O2]2[I–]2[H+]2 c. rate = k[I–][H+] d. rate = k[H2O2][H+] e. rate = k[H2O2][I–]
- Consider the following data concerning the equation: H2O2 + 3I– + 2H+ → I3– + 2H2O [H2O2] [I–] [H+] rate I 0.100 M 5.00 × 10–4 M 1.00 × 10–2 M 0.137 M/sec II. 0.100 M 1.00 × 10–3 M 1.00 × 10–2 M 0.268 M/sec III. 0.200 M 1.00 × 10–3 M 1.00 × 10–2 M 0.542 M/sec IV. 0.400 M 1.00 × 10–3 M 2.00 × 10–2 M 1.084 M/sec The rate law for this reaction is a. rate = k[H2O2]2[I–]2[H+]2b. rate = k[I–]c. None of thesed. rate = k[I–][H+]e. rate = k[H2O2][I–][H+]f. rate = k[H2O2][H+]In an aqueous solution at 25 °C, if [HO] = 9.1 x 104 M, then [OH-] is: 8.0 F3 shot for a F5 F6 8 F7 DII F9 1 4 7 +/- F10 2 5 8 M 3 6 9 0 X C x 10QUESTION 4 Which of the following would be the major product(s) of the reaction below? HBr A. yes B. no OH Br OH Br
