Question: Construct relevant portion of the predominance area diagram of Me-S-O system at 950 K. Show all calculations and indicate the coordinates of the triple point clearly. Using millimetric graph paper is mandatory. Given: Reactions log [equilibrium constant] at 950 K 1) MeS(s) + 2 O2(g) = MeSO4(s) 2) MeS(s) + 3/2 O2(g) = MeO(s) + SO2(g) 3) MeO(s) + O2(g) + SO2(g) = MeSO4(s) log K₁ = 21.59 log K₂ = 18.87 log K3 = 2.72

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Question: Construct relevant portion of the predominance area diagram of Me-S-O system at
950 K. Show all calculations and indicate the coordinates of the triple point clearly. Using
millimetric graph paper is mandatory.
Given:
Reactions
log [equilibrium constant] at 950 K
1) MeS(s) + 2 O2(g) = MeSO4(s)
2) MeS(s) + 3/2 O2(g) = MeO(s) + SO2(g)
3) MeO(s) + O2(g) + SO2(g) = MeSO4(s)
log K₁ = 21.59
log K₂
= 18.87
log K3
= 2.72
Transcribed Image Text:Question: Construct relevant portion of the predominance area diagram of Me-S-O system at 950 K. Show all calculations and indicate the coordinates of the triple point clearly. Using millimetric graph paper is mandatory. Given: Reactions log [equilibrium constant] at 950 K 1) MeS(s) + 2 O2(g) = MeSO4(s) 2) MeS(s) + 3/2 O2(g) = MeO(s) + SO2(g) 3) MeO(s) + O2(g) + SO2(g) = MeSO4(s) log K₁ = 21.59 log K₂ = 18.87 log K3 = 2.72
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