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- Pentaborane BgHg(s) burns vigorously in O2 to give B203(s) and H20(1). Calculate AHrxn for the combustion of 5.00 mol of B5H9. AH(B203(s)) = -1,273.5 kJimol AHAB5H9/s)) = 73.2 KJ/mol AH(H20(0) = -285.8 kJ/mol Multiple Choice - 22.700 kJ - 8,790 kJ 45,400 kJ - 45.400 kJ - 9,090 kJNaOH= (-425.8) CaCl2= (-795.4) Ca(OH)2= (-985.2) NaCl= (-411.2)please show the work clearly
- Use the values of AH to calulate AH for the follonng reactions. Substance and State AH (LJ/mol) Cag(PO,),(s) C&SO (s) CH,(G) HCN(9) HC(G) H,0(g) NH(9) NH,CI(s) 0,(0) HPO,(1) H,80,(1) 4126 -433 -75 135.1 -92 -242 -46 -314 -1267 -814 (2) + N OH 0O AH" b. Caa (PO), (s) + 31, SO.(1) + 3Ca$O.(s) + 2H,PO, (1) c NH3 (g) + HCIG) NH, CI(s) AH"= kJ 888Use heats of formation data bellow to calculate AH° for the reaction: Ca(OH)2 (s) + H2SO 4 () → CaSO4 (s) +2 H20 (1). AH°;(Ca(OH), (s)) = -986.59 kJ/mol AH°;(H2O (1)) = -285.9 kJ/mol AH°;(H2SO4 (1) = -811.32 kJ/mol AH°;(CaSO4 (s)) = -1432.7 kJ/mol AH° = kJ eTextbook and Media Hint Type'here.to search hp 12 47 &Pentaborane B5H9(s) burns vigorously in 02 to give B203(s) and H20(). Calculate AHpxn AH(B203(s)]=-1.273.5 kJ/mol AH{B5H9(s)] = 73.2 kJ/mol AH{H20()) = -285.8 kJ/mol for the combustion of 5.00 mol of BgHg. Multiple Choice 9,090 kJ - 22,700 kJ 1. 45,400 kJ - 8,790 kJ -45,400 kJ Next> LEGO
- OWLV2 | Online teaching and lea X 9 New Tab + x ow.com/ilrn/takeAssignment/takeCovalentActivity.do?locator3Dassignment-take m Week 1 Discussion... MasteringAandP: Q.. P MasteringAandP: S... [References] Use the References to access important values if needed for this question. In the laboratory a "coffee cup" calorimeter, or constant pressure calorimeter, is frequently used to determine the specific heat of a solid, or to measure the energy of a solution phase reaction. A student heats 60.94 grams of silver to 98.31 °C and then drops it into a cup containing 79.27 grams of water at 21.78 °C. She measures the final temperature to be 25.06 °C. The heat capacity of the calorimeter (sometimes referred to as the calorimeter constant) was determined in a separate experiment to be 1.69 J/°C. Water- Assuming that no heat is lost to the surroundings calculate the specific heat of silver. Metal- sample Specific Heat (Ag) J/g°C. %3D Submit Answer Try Another Version 2 item attempts remaining EM…CI Cl2 heat 8⁰ (1) (2) (3) Based on your results for the radical chlorination experiment, predict which products would be most and least abundant in the product mixture. Briefly justify your answer. CIWhat is the enthapy of the reaction of C2H4O + H2 ---> C2H6O in kJ a. -484kJ b. -366kJ c. -48kJ d. 48 kJ e. 366 kJ Please see attached image for structure and bond energies given in problem
