= 250, Rc A typical Wheatstone Bridge is given in the following figure. Here, R₁ = 100, RB 1000, RD = 50 and the resistance of the galvanometer is 3002. The EMF of the battery is 15V. G Vin B Wheatstone Bridge = (a) Find the current in every branch of the circuit. (b) When there is no current in the galvanometer, we say that the bridge is in the equilibrium. Show that, in that case RA = RC RB RD (c) Suppose you are given the task of making the above (non-equilibrium) bridge the equilibrium by adding a resistance. How would you do that?

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter29: Direct Current (dc) Circuits
Section: Chapter Questions
Problem 60PQ: Figure P29.60 shows a simple RC circuit with a 2.50-F capacitor, a 3.50-M resistor, a 9.00-V emf,...
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=
250, Rc
A typical Wheatstone Bridge is given in the following figure. Here, R₁ = 100, RB
1000, RD = 50 and the resistance of the galvanometer is 3002. The EMF of the battery is 15V.
G
Vin
B
Wheatstone Bridge
=
(a) Find the current in every branch of the circuit.
(b) When there is no current in the galvanometer, we say that the bridge is in the equilibrium.
Show that, in that case RA = RC
RB RD
(c) Suppose you are given the task of making the above (non-equilibrium) bridge the equilibrium
by adding a resistance. How would you do that?
Transcribed Image Text:= 250, Rc A typical Wheatstone Bridge is given in the following figure. Here, R₁ = 100, RB 1000, RD = 50 and the resistance of the galvanometer is 3002. The EMF of the battery is 15V. G Vin B Wheatstone Bridge = (a) Find the current in every branch of the circuit. (b) When there is no current in the galvanometer, we say that the bridge is in the equilibrium. Show that, in that case RA = RC RB RD (c) Suppose you are given the task of making the above (non-equilibrium) bridge the equilibrium by adding a resistance. How would you do that?
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